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• � PRESSURE DISTRIBUTION SYSTEM Geotextile fabric
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<br /> 1. 5elect number of perforated laterals�_ uarter inch erforatlons aced�3' .
<br /> ' ' '� ' : <-�;'.:t.9�' af.r�cic
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<br /> 2. Select perforation spacing= • � ..°,'�����,. ""�`.` �
<br /> Perf Sizin�3/16"-1/4"
<br /> 3. Since perforations should not be placed closer than 1 foot to P�SPn�s l.s�-s�
<br /> the edge of the rock layer(see diagram),subtract 2 feet from
<br /> the rock layer length. E-4: Maxinwm albwabla nwr�ber of 1/4inch perforafions
<br /> per laterd to puarcntee<107L discharge variation
<br /> sY�rZi►g -2 ft =�� . . pef�orCl(ofl
<br /> 4. Detemune the number of aces between erforations. `��
<br /> Sp P tee i��ch 1.251nch. T.S•inch 2.O inch
<br /> Divide the length(3)by perforation spacing(2)and�11u,d
<br /> �own to nearest whole number. 2� g �14 18 28
<br /> Perforation spacing=`¢�2_ft+�ft=�_spaces �3.0__ ` 8 13 � 26
<br /> 3.3 7 12 16 � 25
<br /> 5. Number of perforations is equal to one plus the number of 4 0 � �� �5 23
<br /> perforation spaces(4)..Check figure E-4 to assure the number of 5.0 6 10 14 22
<br /> perforations per'Iate�'al guarantees<10%discharge variation.
<br /> � �_3�7aCes+1 =�,=perforations/later2�1 E-6: Parforation Dlscharpa In gpm
<br /> 6. A. Total number of perfora#ions= perforafrons per l�teral (5) perforotion diameter
<br /> times nuinber of laterals(1) �� head �nches
<br /> 7�3�t `s,p. (feet) 3/16 7/32 1/4
<br /> �_perfs/lat x�_lat=�_perforations �,pa 0.42 0.56 0.74
<br /> B. Calculate the square footage per perforation. 2,pb 0.59 0.80 1.04
<br /> Should be 6-10 sqft/perf.Does not apply to at grades.
<br /> Rock bed area= rock width(ft)x rock length(ft) 5.0 0.94 1.26 1.65
<br /> �_ft X�ft- SS o'1 c� sqft a uae t.o toot tw�note-tamny nomes.
<br /> Square foot per perforation=Rock bed area+number of perfs(6) b u�2, reer ror or► i� aige.
<br /> �„EZsqft+�_perfs= 9.2 .sqft/perf ►1NII�p 6pCA7m AT LND OI M[fWl1E qSTRIlUTION ��
<br /> 7. Determine required flow rate by multiplying the Yotal munber of
<br /> perforations(6A).by flow per perforation'(see figure E=6) '�'
<br /> ��Perfs x •--��. ��
<br /> Sb Qvm/perfs=��..SPm .
<br /> 8. If laterals are connected to header. i e as shown on u er ��� {
<br /> P P PP ��"` ,'�;""�,.,
<br /> examp le,to se le c t a i i n i i n u m r e q u i r e d l a t e r a�d i a m e t e r;e n t e r �,,,.�
<br /> fi g u r e E-4 with perforation s pacin g(2)and number of perforations \�
<br /> per lateral(5) Select:runimum diameter for „�,�,,,„.�,�,,,,�,.,��.n�.�,,�,
<br /> NKa1M1[afrll�wr�w w wuro
<br /> perforated lateral= inches.
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<br /> 9. If perforated lateral system is attached to manifold pipe near � , f,� �«�°'"`
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<br /> the center,lower diagram,perforated lateral length(3) and .�.
<br /> number of perforations per lateral(5)will be approxizriately one :.•��,�»�«M
<br /> half of that in step 8. Using these values,select minimum , -,g•�.�,,,�
<br /> diameter for perforated lateral= �) 1Z— inches. a w �, ���,,�
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<br /> I hereby certify that I hav completed this work in accordance with applicable ordinances, rules and laws.
<br /> • (signature) 3�� (license#) l�� � �V 3� (date)
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