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septic design - 2003
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septic design - 2003
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Last modified
8/22/2023 5:02:10 PM
Creation date
3/6/2019 12:43:12 PM
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x Address Old
House Number
749
Street Name
Spring Hill
Street Type
Road
Address
749 Spring Hill Road
Document Type
Septic
PIN
3611823210004
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� ; �MOI�ND DESIGN WORK SHEET(For Flows u to 1200 d) <br /> A. Average Design FLOW A_�; E��tecl Sewo9e Flow:in Gollon:per Day <br /> y��- t�o,�►��- � aS�� u a'� ��'`. <br /> nu r o <br /> Estimated �° O p gpd (see figure A-1) t�.edroom: aau i aau u aau m ciau iv <br /> or measured — x 1.5 (safety factor) _ - gpd 2 � 225 ��o � <br /> 3 . 45p 300 218 of the <br /> 4 600 375 256 values <br /> B. SEPTIC TANK Capacity 5 750 450 294 tn the <br /> b 900 525 332 Class I, <br /> 7 1050 600 370 II,or III <br /> ���o� 1-�00� gallons(see figure G1) 8 �200 675 408 columns. <br /> C. SOILS (refer to site evaluation) c�: s tkTaokCa acities ib� <br /> uq��a���cy <br /> Number of Minimum liqaid liquid capecity with W��disposal8c <br /> 1. Depth to restricting layer= l.s . �. �feet�°►�'`�o+"'�� B�ar°°� c��'ry s�8sedis� liftiaside <br /> 2. Depth of percolation tests = /.2� feet 2«�� �� »� �sao <br /> 3. Texture GL(�^� IAX�1n/1 5a6 is�oo �1.z�so 200° <br /> 3000 <br /> Percolation rate a10. mpi �'8°�9 � 3� <br /> 4. Soil loading rate .4 gpd/sqft(see figure D-33) <br /> 5. Percent land slop� % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow (A) by 0.83 to obtain required ro��C layer area. <br /> �q0 gpd x 0.83 sqft/gpd = � H '7 sqftt�o'�=`��� <br /> 2. D e t e r m i ne rock la yer width= 0.83 s qft/g pd x linear Loading Rate (LLR <br /> 0.83 sqft/gpd x 1Z. gpd/sqft= �fl ft Mound LLR <br /> 3. Length of rock layer= area+width= <br /> ��sqft (D1) + 1�.ft(D2) _�._ft < 120 M PI <� 2 <br /> E. ROCK VOLUME > 120 MPI < b <br /> 1. Multiply rock area (Dl)by rock depth of 1 ft to get cubic feet of rock <br /> ��.sqft x 1 ft=�,�cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> B a Z cuft +27 cuyd/cuft=�.o_cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> �_cuyd x 1.4 ton/cuyd =�3�._tons <br /> A33: Abaorption Width Sfzfng 1ltble <br /> P�ercdation Rate I.wdinY Rue <br /> F. SEWAGE ABSORPTION WIDTH inMinu�esper s«�r�� ���«�= Abcorption <br /> Inch per day per Rsao <br /> � usre foot <br /> F�ater then S Cwrx Sand 1•ZO 1•� <br /> Medium Sand <br /> Lwmy Sand <br /> Absorption width equals absorption ratio (See Figure D-33) <br /> times rock layer width (D2) . 2�0° <br /> �io �i .ao <br /> �— � 46 to 60 Sandy Q�y 0.45 2.67 <br /> 7 _(�n x D �{ = f t Silt Cl�y l.o�m <br /> �.�rs._ <br /> 61 to 120 S ilty Q� 0.24 5.00 <br /> ud <br /> Slower�han 1 0' <br /> •Syaem dadprd tor thw ioib m�a M aher w perfomroee <br />
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