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2005-P09160 - septic
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2005-P09160 - septic
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Last modified
8/22/2023 5:02:07 PM
Creation date
3/6/2019 12:28:15 PM
Metadata
Fields
Template:
x Address Old
House Number
745
Street Name
Spring Hill
Street Type
Road
Address
745 Spring Hill Road
Document Type
Septic
PIN
3611823210003
Supplemental fields
ProcessedPID
Updated
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� � � ��� � � �1�..� Cz�,� . . <br /> MOUND DESIGN WORK SHEET(For Flows u to�1200 d) � � <br /> A. Average Design FLOW n A-t: Estimafod Sewa�o Fl�ws in Gollons per Ocy <br /> '� �° �Q�Yl`c'�'r`�p ; num or o <br /> Estimated �� gpd(see figure A-1) , � � t�d�oom: c�au� ciau u cia�s ni ciass iv <br /> or measured x 1.5 (safety factor) = gp Z �o0 225 �so o� <br /> , • • 3 450 300 218 of rne <br /> � 4 600 . 375 25b" volues <br /> B. SEPTIC TANK Capacity 5 750 450 2�� ' in rhe <br /> /S�O � . c�� �;6��. 900 � 525 332 C�oss i, <br /> � '•"� gallons (See�giire G1) �,� � » � ' 3�o u, cr iu <br /> . 8 1200 675 408 colurnns. <br /> C. SOILS (refer to site evalicatio�i) � c•1: St IICTL11IiC:1 9(IlIt511111':I I011i) � <br /> 2��/ ' LiyuiJ::�p�;m' <br /> ,, Kwobet of Minimum Vquid LiyuiJ capa:in M i�h N i�,Jis�wi�la <br /> 1. Depth to restricting.layer = ��v �7�Z feet .� �.lo &a� c���?� ��a�ra��w�� ��r���s�� <br /> 2. Depth of percolation tests = I,6 - /•/ feet /z '' :«� �so ii's is� <br /> ., <br /> 3. Texture Sc..rc�_o-u:"'�, lo _ ��'►�(�� /�! 3� i� ;� _cwu <br /> Percolation rate y.^9 mpi . �� a 300° 1°�"�n° <br /> 4. Soil loading rate �• d/sqft(see figicre D-33) � . <br /> 5. Percent land slope % • . <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow ��l by 0.83 to obtain required rock layer area. <br /> o Q gpd x 0.83 sqft/gT-�a = �S� sqf� � <br /> 2. Determine rock layer width= 0.83 sqft/gpd x,linear Loading Rate LLR <br /> 0.83 sqft/gpd x % Z- gud/sqft= l U ft M LR <br /> 3. Le n gth of rock la yer=area+width= � �. --- -_ <br /> ��G sqft(Dl)+ I n ft(D2) _ � ft ! � 20 M � �' <� 2 > <br /> E. RQCK VOLUME > � 2O MPI < b <br /> 1. Multiply rock area (Dl)by rock depth of 1 ft to get cubic feet of rock <br /> 7SG sqft x 1 ft= 7sG cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> ��U cuft �-27 cuyd/cuft=�_cuyd - <br /> 3. Mul't,iply cubic yaxds by 1;� to get�•e'ight ofiock in tons ; � <br /> a�S cuyd x 1.4 ton/cuyd = `�'G tons � �G �G <br /> 1?��.75 Abrurptfun WWth SislnK TYbIC <br /> F. SEWAGE ABSORPTION WIDTH ��� �.����� <br /> ..in M�twMts pV $uil Tcaure Galkr�y AII4NTM11M1 <br /> �1IL'�1 �I�f{�ilY�1►f KWIU <br /> ur•li►N <br /> rti.uv uwn s cuu..e s,w, �.:o �.00 <br /> Absorption width equals absorption ratio (See Figure D-33) �y� <br /> times rock layer width(D2) . , � ,,w <br /> w � . 0.50 ..+0 <br /> c�i� x I G f t = 2'`� f t S�u� .6 w eo s,rwr a+r�, o.�s :.o� <br /> s�u ca,� <br /> � � ,�^ 61 a t20 Sih C1�Y U.� S.W <br /> .�' � S r S °-�" ��' �Y�'y <br /> �.�. �.�, . <br /> �A^CF��i'I r' �-' �� �~ � �S�WIM 1kM[I►J MM 11`W ral�II�M At�MMI�M I�'fl�����u�ti� <br /> �� //W/l <br /> V <br />
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