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PRESSURE DISTRIBUTION SYSTEM - ��ric
<br /> �� � '•}•..s:r W'S°�2,�Q„��1��¢;' .�{b�'�'�ySi7L`-"•�'+.�'�.°�i''G�':C�,.�:e
<br /> ��n►;•.�• �G�.` fi'r,.l.'b:'7$��•:4'o:�i :y.�� R6.h9+.wC7.fio- "�. .� .4��."t�
<br /> number of perforated laterals ''�'�_ �^��''.:
<br /> _ inch ntlau 03' �, r,, o�^.
<br /> . ' `•v i��'J�. oe. a�.�.e��-q,�i•..rrC� aa�C' G�.� o r � :J .
<br /> .:-� � • . r?' °� Krt '+rVpYiQdt�ie'v�r• .e.wls�y�y�,�„{„ri�� �� a.
<br /> �2 Select perforation spacing= fee� '',��ac ',c`'"°��,�`' �:'����rj"'�� J � }`
<br /> . -�A. {�a t o �eo'�r.i+;}�'�'c�!rro .. ��^
<br /> , tp
<br /> . . ��a i?i4�o-^v4;a.U,,p!�tD ..;! �:,5..�,..
<br /> � Perf S' ', 7 32" /4" �
<br /> 3. Since perforations should not be placed closer than 1 ft. to P�SP�S 3
<br /> the edge of the rock layer(see diagram),subtract 2 ft. from
<br /> the rock layer length. PoKoratton Di:cherfles in gpm
<br /> �s -2 ft. _ �-3 fee� perfor��l ediameter
<br /> � f�d 1/8' 3/16 1/4
<br /> � .4. Determine the number of spaces between perforations. �,pa 0.18 0.4 0.56 .74
<br /> Divide the length above by perforation spacing and round 2 0�, 0.26 0.59 0.80 �.oa
<br /> down to nearest whole number.
<br /> . 5.0 0.41 0.94 1.26 1.65
<br /> Length perf. spacing= 7� ft.+ 3 ft, -2� spaces b��.o�r r«�-f«nw r,�„�.
<br /> �3) �2) uw 2.o reer r«on,rtnr,�.�e.
<br /> • aot�,aa t«�or,o
<br /> 5. Number of perforations is equal to one plus the number of
<br /> , perforation spaces .
<br /> Maximum numba of quarter inch perforations
<br /> . ��spaces + 1 = �S perforations/lateral ute��t co g�nt�<io��t�e��tion
<br /> Perforatio�
<br /> �;;��.6. Multi 1 erforations er lateral b number of laterals to � s '�'g ! y 2
<br /> _ P Y P P Y gf�t> 1 + 1 �
<br /> \� get total number of perforations. 14 28
<br /> � x �- 7�perforations. 3.0 13 17 � 26
<br /> 3.3 12 16 25
<br /> Calculate the square footage per perforation(6-10 sqft/per� 4.� 11 15 23
<br /> System area:�_x�_= 75° 5.0 10 14 22
<br /> ��� + 7�_ /� sqfdperf
<br /> N.IMOID 6a.,m.T [l0 a.I�/�06iR10V�qN SK7EM
<br /> 7. Determine required flow rate by multiplying
<br /> � number of perforations by flow per„perforat�,on -�x
<br /> �- v 5 � - �/sa „ -p� �N�� s.,�s�, .�._
<br /> 7..� ���_�a sP� _ �-����'''� ��,�.��
<br /> � � �
<br /> 8. If laterals are connected to header pipe as shown on upper `°`��
<br /> ��
<br /> example,to select minimum required lateral diazneter;enter
<br /> table with perforation spacing and number of perforations ,.,p„��.�,�N,��.
<br /> per lateral. Select minimum diameter for ,,,�,,,,,,K,�
<br /> perforated lateral= � � inches. - � � �,,,,.�°�`
<br /> � . . �
<br /> �
<br /> =: 9. If perforated lateral system is attached to manifold pipe near .�-�,�-.�• �
<br /> ,�4 the center,lower diagram,perforated lateral length and - -���
<br /> number of perforations per lateral will be approximately one ,�w �, ,�
<br /> half of that in step 8. Using these va uf�s,select minimum �,ar"� ��=�
<br /> diameter for�perforated lateral=�inches. (�- �
<br /> �
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