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1994-006567 - new septic sysem
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3020 Somerset Lane - 04-117-23-23-0031
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1994-006567 - new septic sysem
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Last modified
8/22/2023 5:10:31 PM
Creation date
2/28/2019 10:19:32 AM
Metadata
Fields
Template:
x Address Old
House Number
3020
Street Name
Somerset
Street Type
Lane
Address
3020 Somerset La
Document Type
Septic
PIN
0411723230031
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET � • <br /> (For Flows up to 1200 gpd) ' <br /> � _ � <br /> A. �.�w Estimated Sewage Flows in Gallons pa day <br /> Estimated '1 c7 p d (see a es D-7 or I-3,4,5) �g�� <br /> �Op P S umber <br /> or measured ._ gpd x 1.5 = -- ���ms Typc I Type lI Type liI I� ' <br /> B. SEPTIC TANK LIQUID VOLIJMES Z 30o Zu �go <br /> 3 450 300 218 �� <br /> 4 600 375 256 ���� <br /> �- ►as� -� )- !oo� gallons (see pages C-3 or C-5) �so 4sc Z�a ;o <br /> 6 900 5?S 332 T��. <br /> 7 1050 600 370 ID <br /> 8 1200 675 408 �d„m,. <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer = l L <br /> t/+� d.�N inches SeDlieTsnk Cyp�cilicX in xylluny <br /> t I ?%umbct of }f:n:mum LiqaiJ LiquW capucity r��ti <br /> 2. Depth of percolation tests = � a inches ���m• c.�.�.y garba�cdip.ixal <br /> 3. Percolation rate 4�.� mpi Z�.ks= ,� >>u <br /> s�a - �an isoo <br /> 4. Land slope '-� % 746 a 9 ��p � <br /> over 9 ••--- <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain requireci area of rock <br /> layer: Daily Flow x 0.83 = , <br /> .2 �_�gpd x 0.83 sq. ft./gpd = �z sq. ft.-r►��=��y� <br /> 2. Select width of rock layer (10 feet or less) _ / v ft. <br /> 3. Length of rock layer = Area-:-Width = <br /> �►-�sq. Et.y ��ft. __�� ft. Rock Bed <br /> . r.f.f.f.f.f.f.r�f���f.f.f.f:f <br /> ti•'.••.•ti•ti•ti•ti•ti . '.•ti•ti•ti• <br /> t•f•f•f•f.f•l•1�J:f•t•f•1•f•t <br /> ti•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti• �dth 5]Oft. <br /> �t•r•r•r•r.r•r•r,f•r.r•r•t•r•r <br /> .�.�.�.ti.�.�.�.. ti.•........ti.•.• 1 <br /> •f.j•;•l•r•,••;•f•,.f.r.;•f•;•f <br /> E. ROCK VOLUME �-- (,ength -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> �sq. ft. x ./ os� ft. _�cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. s 27= �cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd. x 1.4 ton/cu. yd. _�� tons. <br /> F. ADSORPTTON WIDTH �-�`� �-°'�r'' <br /> 1. Percolation rate in top 12 inches of soil is Ss_� mpi Absorption Width SiztngT�bic <br /> Percolation Rat Galbns Ruio of <br /> 2. Select allowable soil loading rate from table on page E-; in Minuterpu s���Trx��� a�d�y�:� Abaorp�ion width <br /> �� ��/f� Inch(MP!) square foa lo Width rer <br /> 3. Calculate adsorption width ratio by dividing rock layer Facterthan 0.1• c�s�,e ----- ____. <br /> o.,w s s�a i.io i.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; o.�a s•• ��sa�a•� o.�o z.�o <br /> 1.20 gpd/ft�i ._y ti`gpd/ftz= a. Lo� 6 to 15 �y� 0.�9 �.s� <br /> 16 to 30 Loam 0.60 2.00 <br /> 31 to 45 Silt I,osm 0.50 2.40 <br /> Check this value on page E-16. �a� �'c�e`Y"° o:i4 s W <br /> 4. Multiply adsorption width ratio by rock layer width to get s���;;;e� c,ay _____ ._... <br /> required adsorption width; <br /> �.(�7x v ft =�ft <br /> 1 <br />
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