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1994-006722 - new septic system
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2990 Somerset Lane - 04-117-23-21-0011
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1994-006722 - new septic system
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Last modified
8/22/2023 5:08:36 PM
Creation date
2/25/2019 1:55:22 PM
Metadata
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Template:
x Address Old
House Number
2990
Street Name
Somerset
Street Type
Lane
Address
2990 Somerset La
Document Type
Septic
PIN
0411723210011
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> � , (For Flows up to 1200 gpd) <br /> A. �,,�w Estimated Seaage Floa in Gailats per Day(gpd) <br /> Estimated �S� gpd N�� <br /> or measured ---- x 1.5 = - gpd. ��„ �'p`r �II TYP�III ry�rv <br /> 2 soo vs �so � <br /> 3 450 300 218 °t <br /> B. SII'TIC TANK LIQUID VOLUMES 4 �ao 3�s zs� .�, <br /> 5 �so aso 29a m <br /> � �)a.�!� � � -/(]0 O g3llOZtS 6 900 525 332 '�'° <br /> 7 IU50 600 370 0� <br /> �.�. <br /> 8 1200 675 408 <br /> C. SOIIS(refer to site evaluation) ,� ,�_ <br /> 1. Depth to restricting layer= 1���To. �y�� inches N� �.�` �,� <br /> 2. Depth of permlation tests = J�_inches ``"" `"�`' <br /> 3. Percolation rate ��i.3 mpi 23 a'a ,'000 ;'w�o <br /> 4. Land slope 3 % ;Q s � �° <br /> . wv 9 See fig.C-6 (x i S) <br /> D. ROCK LAYER DIlvIIIVSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83= , <br /> � D gpd x 0.83 sq.ft./gpd=t�� sq. ft:F�o�o 6454'� <br /> 2. Select width of rock layer(10 feet or less) _ /o ft. <br /> 3. Length of rock layer=azea=width= Rak ged <br /> ��u sq. ft.i JO ft. _ �� ft. ti...�.ti.,.,.,...�.ti.,.�.,.ti...�.� <br /> t•f•rN•I•I•t•f•t•r•I•l•!•f•r•!• <br /> . ��ti�ti�ti�ti���ti�ti�����ti�,�`�����ti�ti <br /> f•r•r•r•r•f•r•r.r r•�•r•J�r•I•J• ldth 510 ft. <br /> ti.ti.�.ti.ti.ti.ti.ti•ti•ti.ti.ti•ti•ti•ti•ti•ti <br /> t•�•l•1•1•J•t•t•f l•f•f•I•I•l•!• <br /> ti.ti•�•ti•ti�ti�ti•ti•1•�•ti•�•t.�•1H.ti <br /> .r.f.l.�.�.f.r.t.f.f.r.f.f•f.f.�. <br /> E. ROCK VOLUME ~- �ng�' -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> (e�4 sq.ft. x ;o ft. _ ��cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yazds; <br /> �S cu.ft. i 27=�cu. yd. <br /> 3. Muliiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd.x 1.4 ton/cu.yd. _�tons. <br /> F. ADSORI''TION WIDTH L.�A y Low n� rKa�,s�, -�bu <br /> 1. Percolation rate in top 12 inches of soil is /q•3 mpi P��,,na,�,� �- a�� <br /> Minu m�;�e, Soil Texture yQ'.y°;,:� �6ed <br /> fa a6eoam <br /> ..ndeh <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 1 zo i.00 <br /> ��t gpd/ft'- 0.1 to� Sand � 1.20 1.00 <br /> 0.1 to� Fine Sand �•� 2•� <br /> 6 to 15 ndv Loam 0.79 1S2 <br /> 3. Calculate adso tion width ratio b dividin rock layer 16�o�o �°�' o-� 2•� <br /> � y g 31 to 45 Silt Loam 0.50 2.40 <br /> loacling rate of 1.20 gpd/ft2 by allowable soil loading rate; �to bo Clav Loam o.�5 2_6� <br /> 1.20 gPd/ft21�gpd/ft�= a•(0 7 Slowerthan 120 Cla"v 0.24 �.00 <br /> "Sal fuving 505G or mare of fine or v�y fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a,c,� x��.ft= a�•� ft <br />
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