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. PRESSURE DISTRIBUTION SYSTEM <br /> AH boxed redangles must be entered,the rest wil/be calculated. <br /> 1. Select number of perforated laterals: 0 �c���;'��a"�° <br /> �irtw�naT +mA O�T t2• <br /> 2. Select perforation spacing= 03 ft Y�.n<•k <br /> r..r s.i..H�i i F•-�i+� <br /> 3. Since perforations should n�be placed closer that 1 foot to �''�`�"^"�s•_s• <br /> the edge of the rock layer(see diagram), subtract 2 feet from <br /> the rock layer len th <br /> 75 -2ft= 73 ft <br /> 4 Determine the number of spaces between perforations. <br /> Divide the length(3)by perforation spacing(2)and round down to nearest whole number. <br /> Perfaation spacing= 73 ft/ 3 ft= 24 <br /> 5. Number of perforat�s is equal to one plus the number of perforation spaces(4). <br /> 'Check figure E-4 to assure the number of perforations per lateral guarantees <br /> < 10%discharge variation. <br /> 24 spaces+1 = 25 perforat�ns/lateral <br /> E-4 Maximun N�nnber of 1/4 Inch perforations E-6 PerForatbn Dlscha in GPM <br /> r lateral to �rantee<70%discha variatbn Head Perforations diameter <br /> p�{�� fcet inches <br /> Spacing 3/16 7/32 1/4 <br /> fcet 1 inch 1.25 inch 1.5 inch 2.0 inch 1a 0.42 0.56 0.74 <br /> 2.5 8 14 18 28 2b 0.59 0.80 1.04 <br /> 3.0 8 13 17 26 5 0.94 1.26 1.65 <br /> 3.3 7 12 16 25 a. use�.o rooe ror singb-tamiy homes. <br /> 4.0 7 11 15 23 b.uae 2.o ree�ror�yu��dsa <br /> 5.0 6 10 14 22 <br /> 6. A Total number of perForatans=perforations per lateral(5)times number of laterals(1). <br /> 25 perfs/lat x 3 laterals= 75 perforati�s <br /> B.Ca�ulate the square footage per perforation. <br /> Recommended value is 6-10 sqff/perf.Does not�py to at-gr�ies. <br /> 1. Rock bed area=rock width(ft)x rock length(ft) <br /> 10 ft x 75 ft= 750 ft <br /> 2. Square foot per perforation=Rock Bed Area/number of perfs(6) <br /> 750.0 ft/ 75 perfs = 10.0 ftZ/perf <br /> 7. Determine required flow rate by muRipying the total number <br /> of perforati�s(6A)by flow per perforations see figure E-6) <br /> 75 perfs x 0.56 gpm/perfs= 42.0 gpm -- - __ _ _ _ __ __ I <br /> .= -- ,.,.,,.. <br /> 8. If laterals are connected to header pipe as shown __=- -- �� <br /> in Fgure E-1,to select minimum required lateral " " .__---_- _ -:--- � <br /> �•:. . -. __;:. <br /> - `--• � <br /> diameter;enter fgure E-4 with perforation spacing(2)and -- - �� ..� <br /> number of perforations per lateral(5). ��.e-�:Mar�oa�ooa�w ae ena or srsam _ _ ____; <br /> Select minimum diameter for perforated laterals= 2.0 inches <br /> 9. If perforated lateral system is attached to manifold pipe �E-�;„�";r,,;�° '�' ' - . l <br /> near the center,like Figure E-2,perforated lateral length(3) � :.;":;; ,_ -- I <br /> and number of perforations per lateral(5)will be approximately � - I <br /> one haff of that in step 8. Using these values,select _ `� ��_ �,, I <br /> minimum diameter for perforated lateral= 1.25 inches. ` - � , <br /> I hereby certify that I have completed this work in accordance with all applicable ordinances, rules and laws. <br /> � �-_ (signature) 810 (license#) 6 /� p�-(date) <br /> Page 1 of 1 <br />