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� PRESSURE DISTRIBUTION SYSTEN� °JD �Fo�'T1°" � A PERFORATED LATERAL <br /> �►w.cw. <br /> 1. Select number of perforated laterals -3 T°°'°° <br /> . �••tr.::,.y;,:... <br /> '�:L`i�'.+.� . . .. (�0y�ef G�otest0e FoOrk(or taJ�� <br /> `a:�.L.oamY SorW�yYr . �a Ych larr el Mp x�frw cow�d <br /> ►'>':, .� ::vh�rW rMln DaW�) <br /> 2. Select pesforation spacing= • � feet. ��a��,,,au���,,,bur <br /> - wa ,n wd Too <br /> 3. Since perforations should not be placed closer than 1 ft. to ''�P�_ " '-'°" 'Z''° Ed°' <br /> oln flsid R o( Redc lara <br /> the edge of the rocic layer(see diagram),subtract 2 ft.from `=:'��'`�'�`��''� ��'`�'�` ��«���'�+.�a� <br /> t�' Clwo Sond ln�r �0�1°of lalard <br /> the rock layer length. � <br /> - .$- U e'i��od°�a sP"0�ona i.oyscar..u�.e <br /> �vY��,�,-7 ft. _ �f� feet. <br /> 4. Determine the number of spaces between perforations. �ry��� <br /> Divide the length above by perforation spacing and round ��. ���. ��r <br /> down to nearest whole number. � <br /> 1.Oa 0.56 <br /> Length perf. spacing = `r�' ft.+ 3 ft. _ �6 spaces 2.Ob 0.80 1.04 <br /> �3� �2� a.Use for singk family homes <br /> 5. Number of perforations is equal to one plus the number of b.Use For all othc appLntiozu <br /> perforation spaces . <br /> �� S 1CeS + 1 = �7 Maximum number of quarter inch perforations pe <br /> p perforations/lateral lateral to guarnantee�1096 dlscharge variation <br /> PerFontion <br /> . 6. Multiply perforations per lateral by number of laterals to S���g 1; 1� 2 <br /> get total number of perforations. 2,5 14 18 28 <br /> ,,3,,� x ���= s� perforations. 3.0 13 17 26 <br /> 3.3 12 16 25 <br /> 7. Determine required flow rate by multiplying 4.0 11 15 23 <br /> number of perforations by flow per perforation 5.0 10 14 2Z <br /> S/ �7y <br /> � X���_38 gpm• WwOLD 10GR0�T CW 0��RCt41�C OKiN�KR�WI SK7ilr <br /> � r.�� <br /> ..��. <br /> • 8. If laterals are mnnected to header pipe as shown on upper � .� <br /> example,to select minimum required lateral diameter;enter . �,��•j <br /> table with perforation spacing and number of perforations ,,.A'° "�'"' <br /> per lateral. Select minimum diameter for �`''"� <br /> perforated lateral = 2 inches. <br /> wair a aran.ss r+a u*cws io. <br /> wat wnw�er w.o�r <br /> ' w�rs w�ns..a <br /> ���7..��`• i�nn�'`� . <br /> 9. If perforated lateral system is attached to manifold pipe near .,,�,,, <br /> the center,lower diagram,perforated lateral length and �;rr�-��--� <br /> number of perforations per lateral will be approximately one ` ` <br /> .._ -,s�rx�r <br /> half of that in step 8. Using these values,select minimum w� .. �,,,�' �-- <br /> diameter for perforated lateral= inches. �,,�'''" ~'�=� <br /> . � .. <br />