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1998-009988 - new septic
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2850 Somerset Lane - 04-117-23-21-0013
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1998-009988 - new septic
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Last modified
8/22/2023 5:08:42 PM
Creation date
2/22/2019 12:58:57 PM
Metadata
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Template:
x Address Old
House Number
2850
Street Name
Somerset
Street Type
Lane
Address
2850 Somerset La
Document Type
Septic
PIN
0411723210013
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Fstimated Sewage Flows in Gallons per day <br /> ( d) <br /> Estimated O gpd Numbv T�� Tra n r�m T� <br /> or measured x 1.5 = gpd. °f <br /> z 3ao zas iso � <br /> B. SEPTIC TANK LIQUID VOLUMES a 6 0 �°s° is� °f� <br /> ��� <br /> Z-/O�o O gallons 6 '�o�o su 3�z Type l. <br /> � ioso 600 3�o u« <br /> 8 1200 675 408 � <br /> C. SOILS (refer to site evaluation) .i `�"""u <br /> 1. Depth to restricting layer = �4� �������������� �� <br /> inches z feet �qwa���Y <br /> 2. Depth of percolation tests = / inches "°^��°� MinimumlJyuid liyuidcaracirywiN ���,�& <br /> Z Bednx�ms Capa[ity gubage dispvsal �h i¢side <br /> 2�xlas 750 1125 I500 <br /> 3. Texture Y�•��►� Percolation rate mpi ;,.<< �� ,� �o� <br /> Surfi I500 2250 3000 <br /> 4. Land slope�_% 7.R ur Y z� 3� � <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> �QO gpd x 0.83 sq. ft./gpd = Soo sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _�ft. <br /> 3. Length of rock layer= area-width = �a 6.e.6.?'g o , �<.e, o d e n a� Q,P <br /> va�o oa'�o ��'e: n ub` <br /> S'O C� sq. ft. = /C� ft. = v�'O ft. A°:�o o nb�D dpeC�q �---�--��:, <br /> QQp,qp,p 9pn:e e e'aoeo O�. <br /> o.00ao oad4000nD vD �p;: ' <br /> Width�ft °000 . ;po.do-don n a oa " <br /> <120mpi <10' Length�o � ftP <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�dOsq. ft. x � <br /> ft. �OC� cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �Sob �u. ft. =27 =��cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;��cu. yd. x 1.4 <br /> ton/cu. yd. _?�tons. <br /> F. ABSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is_�mpi ����� c�,00s �o�rA�� <br /> ) Minutes per inc6 Sal Texnve per day per widt6 to Rock <br /> Textur •4C�✓�-� (MPI) square foot layer VUideh <br /> Fatrcr than 0.1 Coazse Sand 1.20 1.00 <br /> 0.1 to 5 Sard 1.20 1.00 <br /> 2. Select allowable soil loadin rate from table; o.��o s Fine Sand o.�o z.00 <br /> , ,�. � 6 to 15 Sandy L.oam 0.79 1.52 <br /> �� p�d/�2 16 to 30 L.aam 0.60 2.00 <br /> Or 31 to 45 Silt Loam 0.50 2.40 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s�oW�w��zo c,ay o.zo 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2=� 4�-� gpd/ft2= 7��. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> z�X /d � =z�ft <br />
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