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� � MOUND DESIGN WORKSHEET <br /> � , <br /> (For Flows up to 1200 gpd) <br /> j�. �QW Estimued Searagt F7oa in Gallont per Day(gpd) <br /> Estimated�,�gpd N�� Type 1 '(ype II 'iype III Type IV <br /> or measured - x 1.5 = - gpd. s��,T,s <br /> Z 300 Z?S 180 sas <br /> 3 450 300 218 � <br /> B. SEPTTC TANK LIQUID VOLUMES 4 �ao 3�s zs� ..,,,,�. <br /> 1 -J�So � �-/vov gallons 6 '90�o su s3i o� <br /> 7 1050 600 370 �„m„ <br /> 8 1200 675 408 <br /> C. SOILS(refer to site evaluation) <br /> x�nQ � ,�m <br /> �; of �� �.,� <br /> 1. Depth to restricting layer= a� -f� a � inches B�� �,,. ,,� <br /> 2. Depth of pereolation tests = I � inches `""'' ``''�'' <br /> 3. Perrnlation rate I i-)•� mpi Zs a`a` i oso°o i'.'s o <br /> 4. Land slope �-J % ;a g z'� �° <br /> • ovv 9 See fig.C-6 (z 1.� <br /> D. ROCK LAYER DIIvv�II�TSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = , <br /> 7 c� gpd x 0.83 sq.ft./gpd = �a sq. ft.t�o°�o=1��4" <br /> 2. Select width of rock layer(10 feet or less) _ /C� ft. <br /> 3. Lerigth of rock layer= area=width = Rock Bed <br /> ,!o .U sq. ft.1 1�-ft. _�`�ft. �.,.�.,.�.ti.ti.ti.�.�...�.�...�.,., <br /> I•/•1•t•!•f•f•r•f•f•�•J•f•r•1•l• <br /> ti.1•ti•t�ti•ti•ti•t�ti•tiK•ti•V•ti•1•tiK <br /> ti�ti•~�t�tifti�ti�S�ti�ti`ti\ftrti ti ti ti idth <_10 ft. <br /> tifti ti ti ti�lftfti�ti�tf�:�ftiftftiftifl <br /> .f.f.t./.�.f.f.f.r.�.f.f•f.l.f.f. <br /> E. ROCK VOLUME ~- �ng�' -� <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> �sq.ft.x ,o ft. _�cu.ft. <br /> 2. Divide cu.ft.by 27 cu. ft./cu.yd. to get cubic yards; <br /> 71� cu.ft. i 27=�cu. yd. <br /> 3. Multiply cubic yazds by 1.4 to get weight of rock in tons; <br /> �cu.yd.x 1.4 ton/cu.yd. _�l tons. <br /> F. ADSORI'TION WIDTH LLq 4( Lo q r✓� w� tiQ,w�ae,s�, rab� <br /> 1. Percolation rate in top 12 inches of soil is ly•3 mpi Pe�colationRaee �� R�eod <br /> �;,,u��;,,�, Soil Texture �.y,°',:� 1Od`,d,� <br /> Fas abvpea� <br /> `.,dd� <br /> 2 Select allowable soil loading rate from table; Faster than 0.1 oa�sana 1.20 l.00 <br /> � d/ft� 0.1 to� Sand 1.20 1.00 <br /> •� �- � 0.1 to� Fne Sand"' 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1 S2 <br /> 3. Calculate adso hon width ratio b dividin rock layer t6 to 3o i.oam o.bo 2.00 <br /> � y $ 31 to 45 Silt Loam O..iO 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to bo c�ay[.o� o.4s 2.6� <br /> 61 t0120 Clay 024 �.00 <br /> 1.20 gpd/ft��- ,y S �7d/�_ �a •(�� Slower than 120 Clav - - <br /> "Soil having 509G or more af fu�e or very fine sand <br /> 4. Multiply adsorption width ratio by rock layer�vidth to get <br /> required adsorption width; <br /> ?.�� x 10 ft=aU.� ft <br />