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1999-012011 - new septic
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Sixth Avenue North
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4340 Sixth Ave N - 31-118-23-12-0010
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1999-012011 - new septic
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Last modified
8/22/2023 4:28:45 PM
Creation date
2/14/2019 12:52:45 PM
Metadata
Fields
Template:
x Address Old
House Number
4340
Street Name
6th
Street Type
Avenue
Street Direction
North
Address
4340 6th Avenue North
Document Type
Septic
PIN
3111823120010
Supplemental fields
ProcessedPID
Updated
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� • MOUND DESIGN WORKSHEET <br /> � (For Flows up to 1200 gpd) <br /> c r <br /> A. FLOW F.sda�tea sew.t.E1o»a in G,uoni p�r a�r <br /> Fstimated 4Sc� gpd rn� �i �cy�n �cyv�m �v` <br /> or measured --� x 1.5 ==gpd• � <br /> 4 Q00 �37�3 2� nlua <br /> B. SEPTIC TANK LIQtJID VOLTJiV�S s ,� „� � m <br /> ��o.c�_gallons-�s� -� 6 90o szs m r � <br /> 1 - 5�d�+1 f'�ati.�� —'�-V u?��T• i 9 t030 600 770 �a <br /> ! ; i 1200 613 � �� I <br /> C. SOILS (refer to site evaluation) ' i ' <br /> 1. Depth to restricting layer= ����rinches_feet �.� �� �-,� � -��!. <br /> 2. Depth of percolation tests= ���' u►�� '''°°" `'°'°'' °"'"°'''" ��'�` <br /> c.L� w�Y►-� Percolation rate J 3�z- m i '��: �� �� ;� <br /> 3. Texture P s,.. �� � �� <br /> 4. Land slope 3 "�D �o % t.t�r taoo �aoo <br /> D. ROCK LAYER.DiMENSI NS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer. A x 0.83 = <br /> � y�o gpd x 0.83 sq. ft./gpd = 3?�sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = i_ft• <br /> 3. Length of rock layer=area+width= �.� .w . ." <br /> � 3�_sq. ft. + �_ft• _�2_ft• �`•,����'�'� ,* ; � <br /> Width !o ft ' � . . <br /> <120mpi <10' Length 3 � ft <br /> >120mpi c5' <br /> E. ROQC VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�sq. f� x •� � <br /> ft. _�L,cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �,cu. ft. +27=_1��. yd. ! <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;l�cu. yd. x 1.4 ' <br /> ton/cu.yd. =aJL,tons. <br /> F. ABSORP'I'ION WIDTH AbsotpdooWidthSt��Yble <br /> 1. Percolation zate in top 12 inches of soil is 133 mpi ���m ��TQ� �� ��w ' <br /> Texture G��-f u��w� cM� 'a�� �ra�°� <br /> pa.�e.m..q� c,o.r�.s.ea t so �.00 <br /> QI b 3 Saed 1.20 1.00 � <br /> .2. Select allowable soil loadin rate from table; a�p s Fla s°°° a�o �.°° <br /> g 6�o iS SeeQp Le�m 0.79 1.32 <br /> � �d�l�- , �Ia43 SfhLam 030 i40 <br /> �6 a 6p {,o�m 0.43 267 <br /> 3. Calculate adso tion width ratio by dividing rock layer �'°"a'"'�120 � '° 6:° <br /> rP <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading nte; <br /> 1.20 gpd/ft�+ .� gpd/ft�= a-�� <br /> 4. • Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �x.1�_ft= a_�.� ft <br />
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