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Minnesoca-Pollution OSTP Mound Design Worksheet ti �, ^atF <br /> UNIVERSITY �� �-� <br /> >19� Slope OF MINNESOTA '�`:��"`�� <br /> Control Agency r�� <br /> 1• SYSTEM SIZING: Project ID: ���.pq,� <br /> A. Design Flow(Flow&Soi(- 1.A): 450 �Po TABLE IXa <br /> B. Soil Londing Rate(Ftow&Soi(-3.C): 0.60 GPD/ftZ I�OADING RATES FOR DEfERMINING BOTTOM ABSORPTION AREA <br /> I AND ABSORPTION RATI05 USING PERCOLATION TESTS <br /> C.Depth to Limiting Condition: 2.0 ft Trcatment�eve�c Trestment�rvel A,n-2,e, <br /> D.Percent Land Slope: 9.0 % re.co�acton aaee �e�g r,�,una �� tiw,s,e <br /> t�) � nasorpNon R� neaa.pda� <br /> E. Design Media Loading Rate: 1.2 GPDlftZ ��_� R'd° ���� �a° <br /> F.Mound Absorption Ratio(Table IXa): 2.00 ro� - � - � <br /> G.Desiqn Conta�r Looding Rate: 12.0 GPD/ft �o.,co s �.z � �.s � <br /> o.��o s�r�ne sa�e o.e z � �.s <br /> Table 1 �a�w roa hne se <br /> MOUND GUHTOUR IOADING RATES: �6 to t5 0.78 �.5 'I 1.6 <br /> Measuod ' Toxturo-dorivod Contau 16 to 30 0.6 2 0.78 2 <br /> Parc Rate �R nwund absorption ra' L�i� 31 to 45 0.5 2.4 0.78 2 <br /> Rato: <br /> �46to60 0.46 2.6 0.6 2.6 <br /> �60mpi t.0. t.3.2.0.2.�i.2.b �t2 <br /> 6�to t20 - 5 0.3 5.3 <br /> 6t•120mpi OR 5.0 _12 >i20 _ _ _ _ <br /> _i ZO mpi' :s.o• _b• 'Systerta with these values are not Type 1 systems. Contour Loading Rate(linear <br /> loading rate)is a recanrtrended value. <br /> 2. DISPERSAL MEDIA SIZING <br /> A. Catculate Required Dispersa(8ed Area:Design Flow (1.A):Design Medin Loading Rate (1.E)=ft2 <br /> If a larger dispersat media area 450 GPD= 1.20 GPD/ftZ = 375 ftZ <br /> is desired,enter size: �ft� <br /> B. Catculate Dispersa(Bed Width:Contour Loading Rate (1.G):Design Mediv Londing Rate (1.E)=Bed Width <br /> 12.0 ft = 1.2 gpd/ft2 = 10 ft <br /> C. Calcutate Dispersal Bed Lenqth: Dispersal Bed.9ren (2.A):Bed Width (2.6)=Bed Lenqth <br /> 375 ftZ : 10 ft = 38 ft <br /> D. Setect Dispersa(Media: <br /> E. If using a registered product,enter the Component Length: �in= 12 = �ft <br /> F. If using a registered product,enter the Component Width: �in= 12 = �ft <br /> G.Number of Components per Row=Bed Lenqth (2.C)divided by Component Lenqth (4.J)(Round up) <br /> � ft : � ft= �componenu/row <br /> H.Number of Rows =8ed Width (2.6)divided by Component W1dth (4.K)(Round up) Note:CLR of f0.3 <br /> Adjust Contour Loading Rate on Design Summary page until this number is a whole number g°��ft rewlts in 9 foot <br /> wide bed. <br /> � ft' � ft= � rows <br /> �, Tota!Number of Components =Number of Components per Row X Number of Rows <br /> � X � - �componenu <br />