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' � OSTP Pressure Distribution :A <br /> ��' UNIVERSITY i�'` ' "�=',��, <br /> Mmnesota Pollution Desi�n Worksheet OP MINNESOTA '� �� <br /> Controi A enc s�� <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perforated Loterals in system/zone: C� _____ <br /> (2 feet is minimum and 3 feet is maximum spocing) _ <br /> �.,�,.�:,�.�:;«�;.�, - <br /> �� .ti: _ . .` �r-� _ <br /> 2. Setect Perforotion Spacir►g: 3.0 ft ,2'_.. , _. ... „Z-So„ - ; ; - <br /> _� , <br /> -,.� � <br /> P Minimum <br /> `l.'p�rinrations s{�acetl 3'rlWrt � 1'-2'ol rock t2' <br /> 3. Select Perforation Diameter Size 1/4 in _ _ <br /> 6'of ro�k � � � <br /> 4. Length of Latera(s =Media Bed Length-2 Feet. ��w���L=,�w:��•-To`!." PeNorallon spacing:Y to 3' <br /> 38 - 2ft = 36 ft Perforation con not be doser then 1 foot from edge. <br /> 5- Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforntion Spaces = 36 ft .- �ft = 12 Spaces <br /> 6. Number of Perforations per Latera! is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Lateral = 12 Spaces + 1 = 13 Perfs. Per Lateral <br /> Check table below to verijy the number of perforations per lntero!guarantees tess thon o f0%discharge variation. The value is <br /> double if the a center manifold is used. <br /> Maaamum Nc�ber of Perfurations Per LaEee�al to Guarantee�1E!!6 Discharge V�irt� <br /> :.tntfi P �ataons 7f321nch Perforati� <br /> Perforation Spac'sng�Feet} �Pe Diameter(inchesl Perfara6on Spdcing Ptipe Diameter f Inchesl <br /> ! 11G 11� 2 3 (Feetj 1 ik4 t� 3 3 <br /> Z 14 43 18 34 b0 2 ti 1b 21 34 68 <br /> 2v: 8 12 16 26 54 2Yz #0 14 10 33 64 <br /> 3 8 12 tb 25 52 3 9 14 1g 3Q b0 <br /> 3l16 In�t Ferforations 118 inch Perforations <br /> Perforation Spaci��Feetl ���amete��I°xhes� Perfaration Spacir�g Pipe Diameter(lnches► <br /> 1 11� 1t: Z 3 {F�) t tu� 1Vt 2 3 <br /> 2 i2 18 16 4b 87 2 21 33 44 ?4 149 <br /> 2Y� i2 17 24 4Q $0 2f4 20 30 41 d9 135 <br /> 3 12 16 22 37 75 � 20 19 38 64 128 <br /> 7- Tota!Number of Perforations equats the Number of Perforations per Lotera! (Line 6)multiplied by the Number of <br /> Perforoted L.aterals (Line 1). <br /> 13 Perf. Per Laterat X �Number of Perf. Laterals = 39 Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforotion. Recommended value is 4-10 ft Z per perforation. ' PeriantlonD1�'"'�°«°"'� <br /> Does not appty to At-Grades „Q,,�,�� "`�°'°"°"°f�"°°�' <br /> �/a /u '�u �h <br /> Bed Area = Bed Width(ft)X Bed Length(ft) <br /> 1,0' OA6 O.N � O.S6 OJ4 <br /> t.S 0.22 0.51 0.69 0.9 <br /> 10 ft x 38 ft = 380 ttz Za o:� O.S9 O.�D ,.a <br /> Z5 O:H �.65 �.Y9 ,.,� <br /> 3.0 O.12 0.72 O.H .1_2f <br /> Square Foot per Perforation =Bed Areo divided by the Total Number of Perforatior►s (Line 7). •.o 0.3� o.n ,.,� ,..� <br /> 5.0 0.�1� � 0.93 1.36 �1.63 <br /> 380 ft2 = 39 rforations c q,7 2 ,,,,� �'''fe11in$"^�h3/16��chtot/�irc� <br /> Pe ft /perforations �«a« <br /> Dweltlngs with 116Inth pMoratcrs <br /> 2(ce[ OCA�r esfahlislrnMts a�M MSTS wkA 3/t6 <br /> 9. Setect Minimum Average Head: 1.� fC IrcA to t/a incA peAoratbrs <br /> s reee ane.escawkMnena ana Msn.viee t�a incn <br /> pMo2tions <br /> 10. Setect Perforation Dischorye (GPM)based on Table III: 0.74 GPM per Perforation <br /> �1• Determine required Ftow RQte by multiplying the Toto!Number of Perforations (Line 7)by the Perforotion Disclwrge (Line 10). <br />