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- YK�SS UK� U151 K1t3U"1"IUN 5 Y51 CM �eotexuie tavnc <br /> .�; ,�:.. .�.,,;�.� <br /> . , _ -�< ;,, ,, r,.: <br /> ,i- �.i .� ...-~ . . -. <,.�a 4� p w�C.. � <br /> 1: Select number of perforated laterals � �s�n �°�c+o�" •3 1, r " ':`i"�- <br /> ,:. n G <br /> .� u � _� '�.r ` '� � , �� <br /> � � � 7 .-� �rr a a��I��ei � y� ��'�i <br /> 2. Select perforation spacing=�_ft � _ �. �' � '- � <br /> Perf Sizing 3/16"-1/4" <br /> 3. Since perforations should not be placed closer than 1 foot to 1'erf Spacing 1.5'-5' <br /> the edge of the rock layer(see diagram),subtract 2 feet from <br /> the rock layer length. E-4: Maximum allowable nurt�ber oi 1/4-�ch pertora�ons <br /> ' per laterd Io guaadee<l OX�scharge variafion <br /> «k�a�►� -2 ft = � � ft �� <br /> �. Determine the number of spaces between perforations. �� <br /> (tee 1 inch 1.25�ch 1.5 inch 2.0 inch <br /> Divide the length (3) by perforation spacing(2) and�und <br /> down to nearest whole number. z.5 g 14 18 28 <br /> Perforation spacing=�L_ft i � ft= Z j spaces 3.0 8 t3 17 26 <br /> 3.3 7 12 16 25 <br /> 5. Number of perforations is equal to one plus the number of 4 0 � �� �5 23 <br /> perforation spaces(4). Check fcgure E-4 to assure the number of 5.0 6 10 14 22 <br /> perforations per lateral guarantees <IO% discharge variativn. <br /> '�� spaces + 1 = yZperforarions/lateral E-6: Pertorarion Discharge!n gpm <br /> 6. A. Total number of perforations = perforations per lateral (5) perforafion dia eter <br /> times number of lateraLs (1) head inches <br /> (feet) ��8 3/16 7/32 1/4 <br /> �-� perfs/latx 3 lat= �o� perforations <br /> '�1.0° 0.18 0.42 0.56 0.74 <br /> B. Calculate the square footage per perforation. 2.0b 0,26 0.59 0.80 1.04 <br /> Should be 6-10 sqft/perf. Does not apply to at-grades. <br /> Rock bed area = rock width(ft) x rock length (ft) 5.0 0.41 0.94 1.26 l.f�5 <br /> �ft x +�: ft= 6 3� sqft °Use 1.0 fooi tOr singte-family homes. <br /> Square foot per perforation=Rock bed area�number of perfs (6) b u�e z.o reer�o�or+ +� �A. <br /> 1 3c� sqft-�-__S',�_:__perfs = 9',5 sqft/perf <br /> 7. Determine required flow rate by multiplying the total number of � mm � <br /> perforations (6A) by flow per perforation (see figure E-b) � �°oniF""� <br /> i <br /> �C" perfs x •��gpm/perfs= �� SPn' i �� � <br /> $. If laterals are connected to header pipe as shown on upper �•�' <br /> �� <br /> example, to select minimum required lateral diameter;enter aooe�o�o <br /> figure E-4 with perforation spacing(2) and number of perforations� �E_�:������End d System <br /> per lateral (5) Select minimum diameter for <br /> �� <br /> perforated lateral = 'Z inches. �ceete��5� <br /> 9. If perforated lateral system is attached to manifold pipe near <br /> the centez,lower diab am,perforated lateral length (3) and "'°�a1d� <br /> number of perforations per lateral (5)will be approacimately one <br /> half of that in step 8. Using these values,select minimum <br /> �� <br /> diameter for perforated lateral= inches. a�°pi� <br /> ppetomwro <br /> I hereby certi that I ha e co pleted this work in accordance with applicable ordinances, rules and laws. <br /> �� � � (license#) ��/ � �� (date) <br /> (signature) <br />