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1995-007015 - replacement system
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1995-007015 - replacement system
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Last modified
8/22/2023 4:28:21 PM
Creation date
2/13/2019 11:35:16 AM
Metadata
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Template:
x Address Old
House Number
4185
Street Name
6th
Street Type
Avenue
Street Direction
North
Address
4185 6th Avenue North
Document Type
Permits/Inspections
PIN
3111823110004
Supplemental fields
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Updated
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MOUND DESIGN WORKSHEET � <br /> ' ' ; ' (For Flows up to 1200 gpd) . <br /> ' �. FLOW Estimated Sewage Fkrwt in(iallons�x da � <br /> (BPd) y <br /> Estimated �UO gpd (see pages D-7 or I-3,4,5) � <br /> um r <br /> or measured gpd x 1.5 = ��o�m� Typc I Typc II Type 111 �� <br /> 2 300 225 180 <br /> I3. SEPT`IC TANK LIQUID VOLUMES 3 450 3ao Z�a � <br /> 4 G00 375 25G ���� <br /> �- /OD O gallons (see pages C-3 or C-5) s �so 4so 2� ,e <br /> /� �� � � 6 900 525 332 T�Q�. <br /> ( '� 7�C�L M . rii�, 7 1050 G00 370 u� <br /> S 1200 G75 408 �d,o,d <br /> C. SOILS (refer o site eval'uation) <br /> Seplk T�nk Cip�citk;In g�llon� <br /> 1. Depth to restricting layer = 7 inches <br /> Numbct of Minimum l.iquid I.iquiJ capr:ily wi�h <br /> 2. Ueptli of percolation tests = /�? inches ��•�• c.�.���Y `ub��e dixpocsi <br /> 3. Percolation rate mpi � z�ku ��o ��u <br /> 3aa �an �wo <br /> 4. Land slope �� % 748 or 9 'zo�, ;�, <br /> over9 -•-•-- <br /> D. R�CK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x ��=�a,��,,�.f,�„ <br /> '�30U gpd x��sq. ft./gpd = �l�Osq. ft. <br /> 2. Select width of rock layer (10 feet or less) _ /t> ft. <br /> 3. Length of rock layer = Area+Width = <br /> 3 � 1 sq. f t. �- �C f t. _ �f t. Rock Bed <br /> r•r.r.r•r•r•f.f;r;�;�.r•r•r:r <br /> ti•'�•1•'L•ti•ti•ti•t 'L 'L• �•.• <br /> r•l.r.l.r•t t 1:�:1%1.l••%t•1 <br /> ti•ti•ti ti•ti•ti•ti {••. ti••.•ti•ti:ti••.. Wldth S1Uft. <br /> r r•�•r•r.r.'r•r•'r•r•r•r•r.r•r � <br /> ti•{••. 'ti•ti•'L•'..'t ti••.•1•L••.••.••.• I <br /> �f�l�f�f'�r�r�'r�f�,•'f'f',•'••'r'••1 <br /> E. ROCK VOLUME � Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; - <br /> �sq. ft. x % ft. _�cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �lI U cu. f t. +27=�_cu. yd. ' <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd. x 1.4 ton/cu. yd. _ ,,C.(� tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is�mpi Absorpttun Wtdtli Sizing7ablc <br /> Percolallon Ra�c Cellons Re�io of <br /> 2. Select allowable soil loading rate from table on page E-; in Minutc�pc r Soil Tcxture rcr dny�+cr Ahborn��o�W�a��, <br /> � S ��d/r�2 (nch(MPI) squorc foo� lo Rock Lxyer <br /> 1 l- WiJth <br /> 3. Calculate adsorption width ratio by dividing rock layer Faaterthan0.1• c�►�sa,� ..--- ._... <br /> 0.1 to S SenJ l.20 I.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; o.��o s•• Fi�Sand�• o.�o Z.�o <br /> � 6�0 13 Snndy Loam 0.79 1.52 <br /> 1.20 gpd/ft2+_� gpd/ft2= c�• �� �6�0�0 �a�� 0.6o z.�a <br /> 31 l0 45 Silt Loam 2,4p <br /> . Check this value ori �nge E-16. 46a60 ClnyLavn o.a 2.�, <br /> . 4 S.W <br /> 4. Multiply adsorption width ratio by rock layer width to get S��zo;;;�� Clay ---.. __.__ <br /> required adsorption width; <br /> ��x�ft =�ft <br /> J, <br />
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