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1996-008415 - septic
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3240 Sixth Ave N - 29-118-23-41-0005
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1996-008415 - septic
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Last modified
8/22/2023 4:26:53 PM
Creation date
1/23/2019 12:16:46 PM
Metadata
Fields
Template:
x Address Old
House Number
3240
Street Name
6th
Street Type
Avenue
Street Direction
North
Address
3240 6th Avenue North
Document Type
Septic
PIN
2911823410005
Supplemental fields
ProcessedPID
Updated
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, t-ly <br /> ' MOUND DESIGIV WORKSHEE'I' <br /> (For Flows up to 1200 gpd) <br /> A. FLOW D-7 . <br /> [s��urtn sc+r.cc nan m r+un+a�a�.. <br /> Estimated S d gpd (see pages D-7 or I-3,4,5) N,r�(A /�K d II�q�KE• <br /> �o� � a a � <br /> or measured gpd. 2 � � p � <br /> 3 s�p ]pp =�� N <br /> � f0o �7! � +w <br /> B. SEPTIC TANK LIQLTID VOLUMES T ,� � � `'�.`� <br /> Z— /ODOgallons (see pages C-3 or C-5) • �_°° •�° � G� <br /> C-3 <br /> C. SOILS (refer to site evaluation) SEPTIC T�HK C��ACITES, IN GALlONS <br /> „��...�,,. <br /> . 1. Depth to restricting layer = inches "'�" ""'•' '^~°""� <br /> .�. ��,..a.. e,..o... <br /> 2. Depth of percolation tests = I Z inches ,a,,,. ,.. ,,,. <br /> 3. Percolation rate Z > mpi �«� �••• ,f•• <br /> ��. ,... ,... <br /> 4. Land slope �9—� °'o ,,.,a, <br /> .... �.e. <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> ��'o gpd x 0.83 sq. ft./gpd =�7�sq. ft. <br /> 2. Select width of rock layer(10 Eeet or less) _ /O ft. <br /> 3. Length of rock layer= area+width = I <br /> �sq. ft.+ _/O ft. =�ft. Rock Bed <br /> t�t•�•hr•I•r•1•1.1.I.I•f•r 1 � <br /> ti ti ti.�ti•ti•1•�•ti•ti•ti•1•ti•'�•ti• <br /> t•1�1•!•I•I.t•�1•t•t.l•r•I•1 <br /> ti.�.ti.�.ti.ti•ti•�•ti.ti.ti.�•ti•ti.�. idth 510 <br /> I•1.I•1•1•1•�•�r•t•!•�•f•r•/ <br /> ti�U�����•..ti.����ti.ti.ti.�.ti.ti.�� I <br /> �����r�f�f���f�f�r'r'r'1'f'f�f 1 <br /> E. ROCK VOLUME �— ��g� —� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; 37 <br /> ,��sq. ft. x�ft. _�cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu.yd. to get cubic yards; <br /> ��3 cu. ft. i 27=�_cu. yd. <br /> 3: Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> .,f,�,cu. yd. x 1.4 ton/cu. yd. = 2 o tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is�mpi E-16 <br /> 2. Select allowable soil loading rate from table on page E-16; �•�-•-••���.d•e..����.e, j <br /> � <br /> ,�o gpd/ft2 .�...� ..�....,�_��........� � <br /> 3. Calculate adsorption width ratio by dividing rock layer "" """ '""' '""' '""""� <br /> � <br /> ..,. . ,... ..« �.» ,.. <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; � �:N.�_:� �j <br /> 1.2� gpd/ft2 y i bd SPd/ft2 = 2. o o : :i: :;: ::;: ::: ;�e: <br /> Check this value nn page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; i <br /> _�x 2 ft= 20 ft ' <br /> ; <br />
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