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septic info-included design for alternate site
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3060 Sixth Ave N - 28-118-23-32-0014
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septic info-included design for alternate site
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Last modified
8/22/2023 4:24:01 PM
Creation date
1/23/2019 10:17:38 AM
Metadata
Fields
Template:
x Address Old
House Number
3060
Street Name
6th
Street Type
Avenue
Street Direction
North
Address
3060 6th Avenue North
Document Type
Septic
PIN
2811823320014
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ProcessedPID
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, 1VIOUND DESIGN WORK SHEET (For Flows u to 1200 d) <br /> A. Average Design FLOW <br /> '��t,...�+�;;�'�,���,��',,. �,��� A-1: Estimated Sewoge Flows in Gallons per Day <br /> Estimated / '� ( num er o <br /> �- �C� see figi�re A-1) bedrooms Closs i Class II Class Iil Class IV <br /> or measured "� x 1.5 (safety factor) - -� gp 2 300 225 tao � <br /> 3 4� 300 218 of the <br /> B. SEPTIC TANIC Ca acit � �. < < 4 � 375 25e vv�ues <br /> ' p Y �x� ►�'�?���.a �'?•�� :� s �5o a5o 29a in the <br /> 6 � 525 332 Class I, <br /> 1�� '� /n� gallons (see figicre C-1) � �o� �o0 3�o i�, or m <br /> ����9al t"�-1�ti�', �,���,�.�,.,. 8 1200 675 408 columns. <br /> C. SOILS (refQl' t0 SIfe 27JlII1lQf1011� Gl: Se ticTankCa �citieslin allonsl <br /> Number af btinimum Liquid Liquid capxiry u•iIh LiquiJ capacit� <br /> 1. Depth to restricting layer = ;� , �A , feet Bedrooms Ca acitF Nnhdisposal� <br /> P garbage disposal �i(i insidc <br /> 2. Depth of percolation tests = feet � <br /> o�iess �so i i�s <br /> 3. Texture �,.t���ri1 ��l ����4�.-�4 1,�t�vu� 3or4 io� uoo isoo <br /> , <br /> Percolationrate �?,�� mpi 75gaq ;� 3�0 3� <br /> 4. Soil loading rate r lI� gpd/sqft(see figure D-33) �,.,�?�Y�� <br /> 5. Percent land slope `� % ! <br /> D. ROCK LAYER DIMENSIONS <br /> l. Multi ly average design flow (A) by 0.83 to obtain required rock layer area. <br /> � t� gpd x 0.83 sqft/gpd = (ca�'� sqft <br /> 2. Determine rock layer width = 0.83 sqft/gpd x linear Loading Rate LLR <br /> 0.83 sqft/gpd x_ 17, gpd/sqft= /� ft <br /> 3. Length of rock layer = area �width = M O U Cl C� LLR <br /> �.. 4�, � sqft (D1) = �� ft (D2) _ �� ft <br /> < 120 MPI <12 <br /> E. ROCK VOLUME � � 2O M PI <br /> < 6 <br /> 1. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> - �� sqft x 1 ft = aa '�a, cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> ..�u�, �, cuft =27 cuyd/cuft =�_cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> _ `��_cuyd x 1.4 ton/cuyd = �,�A tons <br /> �. SEWAGE AB�ORPTION WIDTH D--�-�� Absorption Wfdth Sizing Tnble <br /> Pcrcolmiun Rulc LawJing Rolc <br /> in Minules per Suil Tcalurc Gullons Ahsnrp�iun <br /> Inch �x:r JaY Ik� R•rtio <br /> (MPI v uurc fool <br /> AUsorption width equals absorption ratio (See Figure D-33) FL��Cr��,�s (a�umySun� �Z� �� <br /> . Medium Sund <br /> times rock layer width (D2) • � <br /> � _ � 16 tn 30 L.00m 0.60 2.00 <br /> . 7 f L l� 31 l0 5 Si t Lomn � <br /> r/�` I�� x ���r� f l = ��_�:� . � .40 <br /> r 46�0 60 Swxly Cloy Iwm 0.45 Z.(7 <br /> Silt Cluy Lnam <br /> '� 61 to 120 Sihy Clay p,2q 5 pp <br /> SunJy Cloy <br /> U <br /> owcr Ihun I 0" <br /> . •Sy+�cm Jenig�nJ f�r�h.xc w�ils musi he�nlwr�.r p:rlorms�cc <br /> .. .. _. ..._. . ....._.. <br />
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