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� . University of Minnesota Pressure Distribution System Design - 10/25/04 <br /> AN bo.red redangles rmist bd entered,fhe�est will be celculahd. <br /> O�ta <br /> se�».�.e <br /> 1. Seled number of perforated laterals: 0 T""`TM� <br /> ►wo�ww� <br /> 2. Selecc;t perforation spacing= Oft <br /> „�.. .��, <br /> 3. Sinoe perforations should not be placed Goser that 1 foot to <br /> tyh�e e�dyge of the r^o�dc layer(see diagram),subtrad 2 feet from '"`."�""'- •"' <br /> llle�lM��'�.�� �l..f.o.�k <br /> 62 -2ft= 60 ft �•�t�.. .y,,.�F--��.- <br /> R f•Y�.��nK 1.5•_S• <br /> 4. Detertnine the number of spaces between perforations. <br /> Divide the length(3)by perforation spacing(2)and round down to nearest whole number. <br /> Perforation spacing= 60 ft/ 3 ft= 20 <br /> 5. Seled perforation size 1/4 inch <br /> 6. Number of peAorations is equal to one plus the number of perforation spaces(4). <br /> `Gieck figure E-4 to assure the number of periwations per latere/guarenNses <br /> <104G dische�ge valietion. <br /> 2p space$+1 = 21 perforations/lateral ' <br /> E•t �n Number of 1/4 tnch perforallons E-6 Maxlmwn Number of 3116 inch perforaHons <br /> ��� ��<10X dlsc va�on labsral to uara�ee<107G discha variatlon <br /> Perforatan <br /> Spaang Pipe Diameder Spaang Pipe Diameter <br /> ft 1 inch 1.25 inch 1.5 inch 2.0 inch feet 1 inch 1.25 inch 1.5 inch 2.0 inch <br /> 2.5 8 14 18 28 2.5 12 19 25 39 <br /> �r .F�.. . �+�:fir�.�' , . ;'��f�,+,���,.�Y-�;_. R�T'u''.,�. <br /> 3.3 7 12 16 25 3.3 10 17 23 36 <br /> �-,: <br /> .�:�� ;a� ���::. "+E .� �"�.'r z.� .^� �'�- <br /> ,�,,..� �_:��.. . <br /> 5.0 6 10 14 22 5 9 15 20 � 31 <br /> 7. A.Total number of perforations=perforations per lateral(5)times number of laterals(1). <br /> 2i perfsl lat x 3 laterals= 63 perforations <br /> B.Ca�ulate the square footage per perforation. <br /> Reoumn�►ded value is fr10 sqNperf.Does not appy to at-grades. <br /> 1. Rodc bed area=rodc width(R)x rock length(R) <br /> 10 R x 62 ft= 620 ft <br /> 2. Square foot per pertoration=Rodc Bed Area/number of perfs(6) <br /> 620.0 ft/ 63 perfs = 9.8 it�/perf <br /> 8. D�i�required flow rate by mulapying the total number <br /> of perforations(6A)by flow per perforations see figure E�) <br /> 63 perfs x 0.74 gpm/pe►is= 46.6 gpm <br /> E�Perforatlon Dkc In GPM <br /> Head Perforations diameter <br /> feet inches <br /> 3/16 7/32 1/4 <br /> 1 0.42 0.56 0.74 <br /> �!�!'�:;�g .�v��'��. j:04 <br /> 5 0.94 1.26 1.65 <br /> a. use t.o toot far sM�gle-famly tames. <br /> b.Use 2.0 feet for . else _ � <br /> ,���, ,., <br /> 9. Detertnine Minimum Pipe Size � ' . ". <br /> A. Manifold on End. If laterals are conneded to header pipe ,, .. , ,, <br /> as shown in Figure E-1,to seled minimum required lateral �..E-,:M���a E„���.�.,�, <br /> diameter,enter figure E-4 or E-5 with perforation spacing and <br /> number of perforations per late�al.Select minimum diameter <br /> for perforated laterals= 2.0 inches <br /> ------ ___..-- - - - - ___ _ <br /> B. CeMer Manffold. If perforated lateral system is attached to �E-�;;,;;�;� ' <br /> manifold pipe near the center,like Fgure E-2,perforated lateral length(3) M ,,, _ ' <br /> and number of perforations per lateral(5)will be approximately ' <br /> one half of thffi in step A. Using these values,select - <br /> minimum diameter for perforated lateral= 1.5 inches - Z_� �'� <br /> I hereby ify that I have completed this work in accordance with all applicable ordinances,rules and laws. <br /> (signature) 810 (license#) 6/29/2005 (date) <br />