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� , Univ�rsity of Minnesota Mound Design Worksheet - 10/25/04 <br /> All boxed rec�angles mUst be entered,the rest will be calculated. <br /> o�:..= <br /> aewuoe <br /> A. Estimated FI 750 gpd(Fig.A-1) TR.��.c�+* <br /> PROORAM <br /> m ewage ows m <br /> Number of Class <br /> Bedrooms I II III IV <br /> 2 300 225 180 60°�of <br /> 3 `: 450 ` ` - .300 ,',2�8 the <br /> 4 600 375 256 values <br /> 'S; 750 ,; .. _ :'450 . �94 , in the <br /> 6 900 525 332 Class I, <br /> .: � _ ����� , � � ;370 II or II <br /> 8 1200 675 408 columns <br /> B. Minimum Se{�ic Tank Capac <br /> S�tic tank c�acity 2250 gallons Number of tanks/compartments �0 <br /> Effluent filter(yes/no) es <br /> C-1 Minimum 'c Tank C in Gallons <br /> Numbe�of Minimum � ap�� � � *GD=garbage disposal <br /> Bedrooms C GDx u in basement** Must have multiple tanks or canpartments <br /> 2�leesss 750 1125 1500 *' Must have multiple tanks,compartrnents <br /> ;�.��`� . ��'.. '��� ` '� � ', '?��.� or effluent scx�een <br /> 5 or 6 r 1500 2250 3000 • <br /> �:: '2Q�., ,R�. . � ":�'� <br /> C. SOILS(SSite evaluafron data) D-33 Abso 'on Width Sizin Table <br /> 1. Depth to restricting layer �5�feet Perc Rate <br /> mpi Sal Texture Loading Rate Absorpbon <br /> 2. Texture lo�n Ratio <br /> Coarse sand,Loamy <br /> 3. Loading rate(see Fig D-33) 0.60 9Pd/� <5 sand,Med�d Fine 1.20 1.00 <br /> sand <br /> 4. Absorption Ra60(Fig D-33J ��'► F��tt�" =' � ':'0.79 :�1.� ; <br /> 16-30 Loam . 0.60 2.00 <br /> 5. Percolationratei�avaiiawe MPI F ;�� �AD <br /> :.�::� .���.�. -_"�r.;. ::�.': i i . . �� <br /> 46-60 Clay loam(CL),Silty 0.45 2.67 <br /> 6. °�Slope 0°r6 or Sandy CL <br /> 61 �ZO �i`�t San�jr = 034� �: �5 � <br /> ��� <br /> >120* <br /> ust o er or ormance. <br /> 0. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow(A)by 0.83 to obtain required area of rock layer: Item A x 0.83= <br /> 750 gpd x 0.83 ft2/gpd 622.5 ftz LLR Chart <br /> 2. Determine rock layer width =0.83 ft/gpd x Linear Loading Rate(LLR)(see LLR chart) Perk Rate LLR <br /> 0.83 ft�/gpd x 12 = 10.0 ft <120 MPI <=12 <br /> 3. Length of rock layer=area divided by width= >=120 MPIt <=6 <br /> 622.5 � � 10 ft = 63.0 ft *or other limited soil conditions <br /> E. ROCK VOLUME <br /> 1. Mulfiply rock area by rock depth to get cubic feet of rock <br /> 622.5 X 1 ft = 622.5 ft3 <br /> 2. Divide ft3 by 27 ft/yd�to get cubic yards <br /> 622.5 ft3 / 27 = 23.1 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 23.1 yd3 X 1.4 ton/yd3 = 32.3 tons <br /> 4. Add in 10%extra for constructability= 1.1 x 32.3 = 35.5 tons <br />