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� ' MOUND DESIGN WORKSHEET t�O�os''�O S i��, <br /> (For Flows up to 1200 gpd) <br /> , , <br /> A. FLOW ��a s�w.8����c.uo�a�a�y <br /> Estimated '1 so gpd r� �,ya i �tya n r,�m ,� <br /> or measured - x 1.5 = -- gpd. <br /> z 3ao ns ieo �,,, <br /> B. SEPTIC TANK LIQUID VOLUMES s .so 30o zis �,� <br /> a 600 37s 256 „�„�, <br /> S 750 450 294 � <br /> •)-l�5�9 b 1- 1 D DO g�011S 6 900 32S 332 Ty�� <br /> ; � 1050 600 370 p a <br /> � ; 8 � 1200 675 I 408 m <br /> edumro <br /> C. SOILS (refer to site evaluation) ,� � ,� ` ,, , <br /> 1. Depth to restricting layer=�TT inches feet ��r <br /> r�e��r �.��+a•w��r«� •�� <br /> 2. Depth of percolation tests= ��`' inches � � �"�' "°'°"°` <br /> 3. Texture Lor.�w� Percolation rate 4, t� mpi 2�,w':' �� �� � <br /> s�K n i?oo 22io 7000 <br /> 4. Land slope � % '•""'" �°°° '°°° i00D <br /> D. R K LAYER.DIMENSI NS . <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> �J o gpd x 0.83 sq. ft./gpd = c..��sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /u ft. <br /> 3. Length of rock layer= area+width= y�.- ,�� -�.�-. <br /> �.,:.�.a o.. +.p�w . <br /> " ��S ft. -t- �_ft. _��ft. ���,d..��:.r� ' , '"'^' <br /> Q• �r!'cya� x p r»; �,.j:a+� . .. �.. <br /> , <br /> �Q" . <br /> Wldth�ft . <br /> <120mpi <10' Length�_ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; loa�. sq. ft. x �-� <br /> ft. _�s� cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �S,'�cu. ft. +27 =a�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;�cu. yd. x 1.4 <br /> ton/cu.yd. _ �,tons. <br /> F. ABSORI'TTON WIDTH ,���ww�s��m� <br /> 1. Percolation rate in top 12 inches of soil is y_�mpi �+�,�e s��T�� v�'� �°m w� <br /> Texture c.�,4�( Lo w-v� c��`i �� ura w�,a� <br /> F��o.� c�s.oa iso i.00 <br /> 0.1 ro S Sood 1.20 1.00 <br /> °� -'� 2. Select allowable soil loadin rate from table; o.��o s F�s� o.�o z.00 <br />•n<2P'*�` g 6 w IS Saody Lam 0.79 1.12 <br /> ��i ' 16 w 30 L.00m 0.60 2.00 <br /> ' SPd�� �i�o,s sin�► oso i.4o <br /> 46 ro 60 Clay Lwm 0.43 2.6'! <br /> . • 60 w 120 Clvy 0.7� 3.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer �'°"a�."'�o c� o�0 6.00 <br /> �,.� - loading rate of 1.20 gpd/ft2 by allowable soil loading rate; ' <br /> �::: 1.20 gpd/ft�+,y�'' gpd/ft2= .a,�� <br /> �,.�.,F. <br /> �= -� <br /> 4. � Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �.�'� x�ft= a�,Zft <br />