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2145 Sixth Ave N - 27-118-23-31-0014
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Last modified
8/22/2023 4:19:42 PM
Creation date
1/17/2019 3:40:12 PM
Metadata
Fields
Template:
x Address Old
House Number
2145
Street Name
6th
Street Type
Avenue
Street Direction
North
Address
2145 6th Avenue North
Document Type
Septic
PIN
2711823310014
Supplemental fields
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, t-ly <br /> ' MOUND DESIGN WORKSHEET <br /> i (For Flows up to 1200 gpd) <br /> � D-7 . <br /> A. FLOW <br /> j Estimated ��O gpd (see pages D-7 or I-3 4 5) a"""""'"°"`°""'"°"'""'°"" <br /> / / NlMf11 I�K 0/�IC7�OfNC(� <br /> ' or measured gpd• "'"� ` II � � <br /> : � � ,.� .� <br /> , � .� � :�. .� <br /> � . � ta0 7T! D� •�w <br /> �n <br /> '� B. SEPTIC TANK LIQUID VOLUMES � ,� ;n � T�;I. <br /> f � �Olo ��00 370 @ <br /> I ��-/C��� � gallons (see pages C-3 or C-5) ' ':°° "' '°' `'W"'" <br /> , C-3 <br /> � SEPTIC T�NK CA��CITES, IN CALLONS <br /> C. SOILS (refer to site evaluation) <br /> i� �� � ��� <br /> 1. Depth to restricting layer = inches .�. ��...d.. .�..o..� <br /> ' 2. Depth of percolation tests = /� inches ,a�,.. �.. ���� <br /> 3. Percolation rate mpi '°"' "" "" <br /> .�. ,... ,��. <br /> 4. Land slope % •.��� ,••• '••• <br /> � D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> � layer: A x 0.83 = <br /> ' �-�gpd x 0.83 sq. ft.lgpd =S��sq. ft. <br /> 2. Select width of rock layer(10 feet or less) = /+n ft. <br /> � 3. Length of rock layer= area+width= Rock Bed <br /> ; —c� s q. ft.+ 1�_ft. =-S�O ft• <br /> . . .f. f•r r•i•��r r•t•r <br /> ♦��ti.?�.�ti•�ti•��•�.�.ati• <br /> I ..�'�;:ir���:tir�:tif�=ti�ti:tir4:tis idth 510 <br /> .i:�•r•�•7�r•}.r. }r.r•r r•r <br /> .ti.s t.� ti•ti ti•t��,.ti.ti.ti.L.�• <br /> .r.�.}.r}.r. .f.r. .f.I'•/•r./ <br /> E. ROCK VOLUME '�---- ��g� <br /> 1. Mulriply rock area by rock depth to get cubic feet of rock; <br /> , So� sq. ft. x / ft. �� cu. ft. <br /> ; <br /> 2. Divide cu. ft. b y 27 cu. ft./cu.yd. to get cubic yards, <br /> �G� cu. ft. +27'=�_.cu. yd. <br /> 3. Multi ly cubic yards by 1.4 to get-weight of rock in tons, <br /> , � /��cu, yd. x 1.4 ton/cu. yd, =��tons. <br /> ; <br /> i <br /> j F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is�;mpi, E-16 <br /> � 2. Select allowable soil loading rate from table on page E-16; ����ma���^u�°°�°, ` <br /> ' �{z` �pd/ft2 � ..�...,....�. I <br /> , '.M. ..�. w... .�... �.'�.: � <br /> � 3. Calculate adsorption width ratio 1�q'dividing roek layer �, � �„ �w �N „� <br /> ' loading rate of 1.20 gpd/ft2 by allowable soil loading rate; � '" '�" �C#'� <br /> .... ..�� <br /> ' 1.2�gpci/ft21�BPd�ft2= �'.i� :: ... .... ::: ': ,.., <br /> ., .,�. ..�. ..,. .... ,.. <br /> Check this value on'page E-16. <br /> � 4. Multiply adsorprion width ratio by rock layer width to get <br /> , required adsorption width; � � <br /> � �O x z ft =�� ft <br /> � <br /> ' -� �— ' ;;�- � ,�� �`�-`` <br /> I . . . . �A�. . � . . <br /> � ?�'��T� .. ' . <br /> � <br /> i <br /> 1 <br />
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