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1995-007167 - new septic
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1870 Sixth Ave N - 27-118-23-42-0022
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1995-007167 - new septic
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Entry Properties
Last modified
8/22/2023 4:22:22 PM
Creation date
1/16/2019 11:41:48 AM
Metadata
Fields
Template:
x Address Old
House Number
1870
Street Name
6th
Street Type
Avenue
Street Direction
North
Address
1870 6th Avenue North
Document Type
Septic
PIN
2711823420022
Supplemental fields
ProcessedPID
Updated
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G: DO'vVNSLOPE DIICE WIDTH . ; <br /> 1. If landslope is 3% or more,subtract rock layer width from <br /> adsorption width to obtain minimum downslope dike toe <br /> � •`ft-�ft =�2_feet <br /> 2. Calculate Minimum mound size based on geometery: <br /> a. Determine depth of clean sand fill at upslope edge of rock <br /> layer: Separation 1. S� feet <br /> b. Multiply rock layer width by landslope ;� rooc co�.�: <br /> to determine drop in elevation; ` � g.�� + r o o t R o �a <br /> Slope Diffel'e11CB s��eret�on t��t <br /> _�X�o _%1100 =�¢_feet s�ovs ort�sronce _c�: et <br /> UDs1oDe Wldt� <br /> c. Add depth of clean sand for separation (2a) -U--teet Ro�k eea w�ecn <br /> at upslope edge,depth of rock layer(1 foot) to depth of ��eet DownsloDe W1Gth <br /> cover(1 foot) to find the mound height at the upslope edge 3�teet <br /> of rock layer; ' <br /> 1,�ft + lft+ lft= 3.� feet ' <br /> d. Enter table with landslope and upslope dike ratio. <br /> Select dike multiplier of 3•a� <br /> e. Multiply dike multiplier by upslope mound height <br /> to find upslope dike width: 3-� x 3.�� _�_ feet <br /> f. Add depth of clean sand for slope difference (2b) at <br /> downslope edge,to the mound height at the upslope edge <br /> of rock layer (2c) to find the downslope height; <br /> 3.� ft + , b ft= 4. r feet • <br /> g. Enter table with landslope and downslope dike ratio. <br /> Select dike multiplier of S,a �. <br /> h. Multiply dike multiplier by downslope mound height <br /> to get downslope dike width: 4• 1 x S.z.b�= 3�feet � <br /> i. Compare the values of step G.1 and Step G.Zh Select the <br /> greater of the two values as the downslope dike width; <br /> a� feet . .:.:.:.. , <br /> � ' :EUD510DY M10th. � ....: .i .�: �-: <br /> te�[ :?1`ii;:?::::?:?i:i:i:z:1::;i:i:::E:i::;':.i..:.::::...:......;....:..........;i...._..:.:..:i� <br /> wi th is the sum of >::::::..�l-.-.�:..::::.:::. :;><,;;;.;.;;<;:::::::<.;;;:;:.;::::.,:;;::,:;::::.:.::::;::::.<::.:::,::.;: <br /> j. Total mound d """ <br /> .............._..... ... ,..;::.::;.::.:::: <br /> u r ck o� <br /> a W�a�� <br /> . � <br /> 1 s o <br /> ' e G <br /> .2e wid <br /> u slo dik <br /> ( ) <br /> P <br /> g <br /> P Pe <br /> 0 <br /> � � <br /> i �. <br /> r.. <br /> layer width (D.2)plus � �os�oo•w,Q�� ��°_�,�w'°t" <br /> - reet <br /> downslope dike width(G.2i}; o � � . test <br /> _�ft+ 1D ft +� ft = t�� feet � T ' � ` ; <br /> � �: ,DownsloDe WIOt� �� <br /> k. Total mound length is the sum of � ; ��ea� < <br /> upslope dike width (G.2e)plus rock layer <br /> : <br /> len h (D.3)plus upslope dike width (G.2e); � ' <br /> � E ; <br /> I 1 ft + SS ft +�ft = �_ feet > <br /> �� -�- SS -r aa = 99 ��' - <br /> 7otet�engtn �� <br /> owns ope ps ope <br /> 3:1 l•1 i:1 &t 7:I 3:1 4:1 5:1 &1 7:1 8:1 <br /> %abpc <br /> 0 3.0 LO �.0 6.0 7.0 3.0 4.0 5.0 60 7.0 8.0 <br /> 1 3.09 417 i.�a 633 753 ?91 3.8i A.76 i.66 l id 7.d1 <br /> ? 3.19 d3i i�e 6.52 8.13 2.&3 3.70 d56 �36 614 6.90 <br /> 3 330 i_i4 i.88 7.3? 6.So 2T� 3�� 43i 5.08 5.79 6Ai <br /> d 3.d1 `76 S?5 7.39 9.T1 263 3.ii i.ti 6.83 5.�6 6.06 <br /> 5 353 5.pp 667 8�� IO.TI Z61 3.33 6.OD 4.62 �.19 �.T <br /> 6 3b6 G.�?b��'. 7.1d. 9.35_.... ..12Q7 Zi0 �3-Z31 3.&S i61 4.93 5.41 <br /> 7 3�0 i56 7.FA. . . ..I033 .. . 1373 -2.i4 312 3.70 6.23 aro 513 <br /> 8 3.95 5.88 833 71�-i 1591 242 3.C3 3S7 tn5 0.09 4B6 <br /> 9 t.11 b.?5 9.09 13.65 IS.92 230 296 3.45 3.90 Q30 �4.6i <br /> �p 4.29 667 10.0 I5.00 2333 ?�'i ZHo 333 3.75 4.12 4.i1 <br /> Il 4.68 7.14 It.11 17.bi 30.33 2.2b 213 313 3.61 3.95 42b <br /> 7? db9 7.69 1Li0 2i.:3 43.75 Z21 ZiJ 3.i2 3.69 3.80 4.08 <br />
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