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F. ' ABSORPTIONYYIDTH • Absorption ratio: 2 <br /> 1. Absorption width equals absorption ratio times rock layer width <br /> p,pQ x 10.0 ft = 20.0 ft <br /> G. MOUND SLOPE WIDTH 8�LENGTH(Greater than 1%) <br /> 1, Downslope abso�ption width=absorption width minus rock layer width <br /> 20.0 feet - 10.0 feet= 10.0 ft <br /> 2. Calculate mound size <br /> � UPSLOPE � � <br /> a.Depth of clean sand at upslope edge of rock layer=3 feet minus distance to restricting layer(C1) <br /> 3.0 ft - 2.0 ft= 1.0 ft <br /> b.Mound height at the upslope edge of rock layer=depth of clean sand for separation(G2a) <br /> at upslope edge plus depth of rock layer(1 foot)to depth of cover(1 foot) <br /> 1 ft+1ft+1 ft= 3.0 ft <br /> c.Upslope berm multiplier based on land slope(see figure D-34) <br /> Selected bertn multiplier. <br /> d.Upslope width=berm multiplier(G2c)times upsiope mound height(G2b): <br /> 0.00 x 3.0 ft = 9.0 ft <br /> DOWNSIOPE <br /> e.Drop in elevation=rock layer width(D2)times percent landslope(C5)/100 <br /> 10.0 ft x 12.0 % /100= 1.2 ft <br /> f.Downslope mound height=depth of clean sand for stope difference(G2e} <br /> at downslope rock edge plus the mound height at the upslope edge of rock layer(2b) <br /> 1.2 ft + 3.0 ft= 4.2 ft <br /> g.Downslope berm multiplier based on percent land slope(see Figure D-34 <br /> Selected berm multiplier: 4.69 <br /> h.Downslope width=downslope multiplier(G2g)times downslope mound height(G2� <br /> 4.69 x 4.2 = 19.7 ft <br /> i.Select greater of G1 and G2h as the downslope width 20.0 ft <br /> j.Total mound width is the sum of upslope(G2d)width pius rock layer width(D2)plus downslope width(G2i} <br /> 9.0 ft+ 10A ft+ 20.0 ft= 39.0 ft <br /> k.Total mound length is the sum of upslope width(G2d)plus rock layer length(D3)plus upslope width(G2d) <br /> 9.0 ft + 34.0 ft+ 9.0 ft= 52.0 ft <br /> Final Dimensions slope>1%) 39.0 ft x 52.0 ft <br /> I hereby rtify that all work has been compieted in accordance with all applicable ordinances,rules&laws. <br /> (signature) 810 (license#) 10116/2� (date) <br /> Page 2 of 5 <br />