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� PRESSURE DISTRIBUTION SYSTEM <br /> All boxed rectangles must be ente�ed,the rest will be cakulated. <br /> 1. Seled number of perforated laterals: 03 ���-����•«^� <br /> , <br /> �a..�..��.,e,o...�, , .�. <br /> 2. Seled perforation spaang= �ft �.,��.,•k <br /> r�`t.`i ss•y��`.vi i�s_s�ia- <br /> 3. Since perforations should not be placed Goser that 1 foot to <br /> the edge of the rock layer(see diagram),subtract 2 feet from <br /> the rodc layer len h <br /> 50 -2 ft= 48 ft <br /> 4 Determine the number of spaces between perforations. <br /> Divide the length(3)by perforation spacing(2)and round down to nearest whole number. . <br /> Perforation spaang= 48 ft/ 3 R= 16 <br /> 5. Number of perforations is equal to one plus the number of perforation spaces(4). <br /> 'Check figu�E-4 to assure the number of peiforations per latera/guaranfees <br /> <1096 disdrarge variation. • <br /> 16 spaoes+1 = 17 perforations/lateral <br /> E�Ma�dmum Number of 1/41nch pertontions E-8 Perforation Discha in GPM <br /> laberal to uaranbee<70X discha varlatlon Head PerForations diameter <br /> pe��p� feet inches <br /> g�p�y 3/16 7l32 1/4 <br /> feet 1 inch 1.25 inch 1.5 inch 2.0 inch 1' 0.42 0.56 0.74 <br /> 2.5 8 14 18 28 2b 0.59 0.80 1.04 <br /> 3.0 8 13 17 26 5 0.94 1.26 1.65 <br /> 3.3 7 12 16 25 a. Use 1.o roa ror sirple-famiy nomes. <br /> 4.0 7 11 15 23 b.Use 2.0�for a i �se <br /> 5.0 6 10 14 22 <br /> 6. A Total number of perforations=perforations per lateral(5)time.s number of laterals(1). <br /> 17 perfs/lat x 3 laterals= 51 perForations <br /> B.Calailate the square footage per perforation. <br /> Recammended value is 6-10 sqft/perF.Does not apply to at�rades. <br /> 1. Rodc bed area=rodc width(ft)x rodc length(ft) <br /> 10 ft x 50 ft= 500 ft� <br /> 2. Square foot per perforation=Rock Bed Area/number of perfs(6) <br /> 500.0 ft� / 51 perfs = 9.8 ft�/perf <br /> 7. Detertnine requir�ed flow rate by multiplying the total number <br /> of perforations(6A)by flow per perforations see figure E-6) <br /> 51 perfs x 0.74 gpm/perfs= 37.7 gpm _ _ ____--_ _ _____---. _ _ <br /> � R , <.F_ <br /> 8. If laterals are conneded to header pipe as shown ! _ - ��� � <br /> in Figure E-1,to select minimum required lateral � � �� � - ". <br /> diameter,enter figur+e E-4 with perforation spacing(2)and __ " � � ,�, <br /> , � .... .. <br /> number of perforations per lateral(5). �Fa�••E-,:M�w��»e a E^a a�„ <br /> Select minimum diameter for perforated laterals= 2.0 inches <br /> 9. If perforated lateral system is attached to manifold pipe �E•¢�� "' '. <br /> In Gnhr of M M� <br /> near the center, like Figure E-2,pertorated lateral length(3) � r,„ _ - <br /> and number of perforations per lateral(5)will be approximately : �r�;, ` _ <br /> one half of that in step 8. Using these values,select : ��= ,�,,�, <br /> minimum diameter for perforated lateral= 1.5 inches. ` � �, <br /> I here certify that 1 have completed this work in accordance with all applicable ordinances,rules and laws. <br /> (signature) 810 (license#) �/ O (date) <br /> Page 1 of 1 <br />