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. , <br /> . i <br /> Mound Design Worksheet (For flows up to 1200 gpd) <br /> Ail boxed recfangles must be entered,the nest wi116e calculated. <br /> A. FLOW <br /> Estimated 600 gpd(see figwe A-1) <br /> or measured x 1.5(safety factor)= 0 gpd <br /> B. SEPTIC TANK LIQUID VOLUMES <br /> S�tic tank capacity 2000 galbns(see figwe G1) <br /> c an apac in a ons <br /> Number of Minimum Capaaty with Capacity with <br /> Bedrooms Capaaty Garb.Disp. Disp.and LiPt <br /> 2 or less 750 1125 1500 <br /> 3 or 4 1000 1500 2000 <br /> 5 or 6 1500 2250 3000 <br /> 7,8 or 9 2000 3000 4�0 <br /> C. SOILS(Site evaluafion data) <br /> 1. Depth to restricting layer- 2.1 feet <br /> 2. Dep1h of peroolation tests= 12 im�hes <br /> 3. Texh�re sand bam <br /> 4. Soil bading ra�(see F'gwe D-33 0.79 gpol ft <br /> peroolation rate 3 MPI <br /> 5. 96 l.ar�d Sbpe 11 % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Mul�ply average design flrnv(A)by 0.83 to obtain requi�ed area of rock layer.Item A x 0.83= <br /> 600 gpd x 0.83 it�gpd= 498.0 ft� <br /> 2. Detertnine rodc layer width =0.83 ft�/gpd x Linear Loadin Rate LLR)(see LLR chart) <br /> 0.83 ft�/gpd x 12 = 10.0 R <br /> LLR Chart <br /> Perk Rate LLR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Length of rodc layer=area divided by width= <br /> 498 fl/ 10 feet= 50A feet <br /> E. ROCK VOLUME <br /> 1. Mulbply rock area by rodc depth to get cubic feet of rodc <br /> 498 X 1 ft= 498.0 ft3 <br /> 2. Divide ft3 by 27 ft3/yd3 to get cubic yards <br /> 498.0 ft3 / 27 = 18.4 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rodc in tons; <br /> 18.4 yd3 X 1.4 ton/yd3 = 25.8 tons <br /> F. ABSORPTION WIDTH <br /> 1. tion width uals absorption ratio(see Figure D-33)times rodc layer width <br /> 1.5 x 10.0 R = 15.0 ft <br /> Page 1 of 6 <br />