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University of Minnesota Pressure Distribution System Design -10/25/04 <br /> a oaroa�ecarwbs,�w.,r ce��,ea,a��ssr�►ce ceran�ea. <br /> oN.... <br /> s■w..s <br /> 1. Selecx number of perforated laterals: �3� '��'�""" <br /> Z. SeleCt peAofaqon spacing= �3_]ft <br /> <:...,�.k...,.... <br /> 3. Since perforatlons should not be piaoed Goser fhat 1 foot to - _ _ _.-- <br /> per �•- <br /> t•h�e edge of fhe rock Iayer(see diagram),subtrad 2 feet from �-��""_�...•,"..�_-"-=�"'•-�� ._. <br /> I v..r...k <br /> u���� 14rt tidnK�/��•-1/+' <br /> 50 -2 ft= 48 fl ���!�"'�Mt�4•_S• <br /> 4. Detertnine the number of spaces between perforations. <br /> Divide�e bngth(3)by perforation spaang(2)and round down to nearest whole number. <br /> PeAoration spaang= 48 ft/ 3 ft= 16 <br /> 5. Select perforation size 1/4 inch <br /> 6. Number of perforations is equal to one plus the number of pe�toration spaces(4). <br /> •C�/igure E--4 to assu�e tl�e numberofperfona6ions perletersl guaiantees <br /> <t0%dische�e varis6on. <br /> 16 spaoes+1 = 17 perforationsAateral <br /> E�4 um Number of 1l4 iach -5 um umbst of 3/16 inc <br /> ��p <10SG disc vsryqon lalsral to <10X discha varlatfon <br /> pe�pp� Pe <br /> spacirq Pipe nien►arer spacinp Pipe viamerer <br /> R 1 k�ch 1.25 inch 1.5 inch 2.0 inch feet 1 inch 1.25 inch 1.5 inch 2.0 inch <br /> 2.5 8 14 18 28 2.5 1 19 25 39 <br /> 3A $ 13 - 17 �8 3 13 18 Z4 37 <br /> 3.3 7 12 16 25 3.3 10 17 23 36 <br /> �4.Q : 7 11 13 23 4 :10 18 21 $3 <br /> 5.0 6 10 14 22 5 9 15 2�) 31 <br /> 7. A.Total number of perforations=perforations per lateral(5)times number of laterals(1). <br /> 1 T parfs/lat x 3 laterals= 51 perforotions <br /> B.Calalate the aquare footage per perf�ion. <br /> Reoonwnsnd�ed value is 6-10 sqft/perL Does not appy to at�►ades. <br /> t. Rodc bed aroa=rodc width(R)x roc;k length(ft) <br /> 10 ft x 50 ft= 500 R� <br /> 2. usre per perforation=Rodc 8ed Arealoumber of perfs(6) <br /> 500.0 tl� / 51 perfs = 9.8 ft/perf <br /> 8. DeUertnine required fbw rate by muldplying the total number <br /> of perforations(6A)by flow per perforatans aee figure E�) <br /> 51 perts x 0.74 gpm/perfs= 37.7 gpm <br /> E-a ratlon Dbc In tiPM <br /> Flead Per�orations dismeter <br /> feet ind�es <br /> 3/16 7/32 1/4 <br /> 1 0.42 0.56 U.74 <br /> �° o.ss o.so �.a <br /> 5 0.94 1.26 1.65 <br /> a use t.o foa r«dnpsra�ray nomes. <br /> 0.Use 2.0 teat tor Nae . <br /> . '�/ . <br /> 9. Detertnins Minimum Pipe Size ' , <br /> A. Msnifold on End. It laterals are connected to header pipe <br /> as shown in Figure E-1,to selec3 minanum required lateral Fq�wE-1:NOYbldloeal�OarEnOafMMn <br /> diameter,enter figure E-d or E-5 with perforation spaang and <br /> number of peAorations per lateral.Select minimum diameter <br /> for peAorated laterals= 2.0 inches <br /> B. Ce�rte�M�nifold. If perforated lateral syst�n is aUached to w�FxM��� • <br /> manifold ~ `N`a�`�'"`"� , <br /> ppe near the center,like Figure E-2,perforated lateral length(3) <br /> and number of peAorations per lateral(5)will be approximately - ' <br /> one half M that in step A. Using these valu�,selec:t - <br /> minimum diart�ter for perforated lateral= 1.5 inches • Z_ <br /> f hereby ' that I have completed this woAc in acoordance with atl applicable ordinanoes,rules and laws. <br /> / -_. <br /> (signature) 810 (license#) 12/18l05 (date) <br /> c'� <br />