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PRESSURE DISTRIBUTION SYSTEM - Trenches
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<br /> All boxed rectangles must be entered,th@/8St wlll b@ C8/Culeted. v..��r�,�-k
<br /> r�.c>�s��n�i ie^-�ia,.
<br /> 1'vrF S�ar�n�1.5•_5'
<br /> 1. Select number of perforated laterals: Q
<br /> 2. Select perforation spacing= �3 ft Fa n+w.r..r,��en,��►�ie-:�n�ra�
<br /> pw blad b o�aniea<t O%dbcharpe vaialion
<br /> 3. Since rforations should not be laced closer that 1 foot to °e"°`°r°"
<br /> Pe P sva�+a
<br /> the edge of the rock layer(see diagram), subtract 2 feet from r� ��n �.z�r,�r, �.s x�n z.o��n
<br /> the rock la er len th 2.s g 14 �e za
<br /> 50 -2 ft= 48 ft s.o s ia i� ze
<br /> rock layer length 3.' ' 'z '° n
<br /> 4.0 7 11 15 23
<br /> 5.0 b 10 14 22
<br /> 4 Determine the number of spaces between perForations.
<br /> Divide the length (3) by perforation spacing (2)and round down to nearest whole number.
<br /> Perforation spacing= 48 ft/ 3 ft= 16 spaces
<br /> 5. Number of perforations is equal to on�plus the number of perforation spaces(4).
<br /> 'Check figur�s E-4 to assure the number of perforations per lateral guarantees
<br /> < 10%discharge variation.
<br /> 16 spaces+ 1 = 17 perforations/lateral
<br /> 6. A. Total number of perforations=perforations per lateral(5)times number of laterals(1).
<br /> 17 perfs/lat x 3 laterals= 51 perforations
<br /> E-6: Perfaa�on Dlscharqe in pxn
<br /> B. Calculate the square footage per perforation. perrorot�on d�ometer
<br /> Should be 6-10 sqft/perf. Does not apply to at-grades. �Inches
<br /> 1. Rock bed area=rock width (ft)x rock length (ft) ��a 118 3J1 b 7132 t/4
<br /> 10 ft x 50 ft= 500 ft j,po 0.18 0.42 0.56 0.7d
<br /> 2. Square foot per perforation = Rock Bed Area/number of perfs(6)
<br /> 500.0 ft/ 51 perfs = 9.8 ft/perf 2.ob o.26 0.59 0.8o t.04
<br /> 5.0 0.41 0.94 1.2b 1.65
<br /> 7. Determine required flow rate by multiplying the total number «usN,o r�..,,r_,���,a��.�,1��,��������g.
<br /> of perforations(6A)by flow per erforations(see figure E-6) ���s��o r:,:-,r�,����� ,�,�,- ��:.
<br /> 51 perfs x 0.56 gpm/perfs= 28.6 gpm
<br /> � ----- --__ ___ __.__._
<br /> 8. If laterals are connected to header pipe as shown I -
<br /> - ,� ,„�., . .
<br /> in Figure E-1, to select minimum required lateral , _- > ''`�Y � �
<br /> diameter; enter figure E-4 with perForation spacing (2)and ; a`~"` . : '• '
<br /> number of perforations per lateral (5). � - `� , ,„ '
<br /> ,
<br /> � Flqurr E-1:MonNold Looahd d End of Sysl�m '
<br /> Select minimum diameter for perforated laterals= 02 inches
<br /> 9. If perforated lateral system is attached to manifold pipe Rpw E•2:ManlbW L000Mtl � -
<br /> In MN CMNr o11M BV�Nm ..�•
<br /> near the center, like Figure E-2, perforated lateraf length (3) ,
<br /> and number of perforations per lateral (5)will be approximately =- � , ' �
<br /> one half of that in step 8. Using these values, select � �'• - _
<br /> •- ._,,,_ ,.
<br /> minimum diameter for perforated lateral= Dinches. _- �_ �`
<br /> I hereb rtify t I hav ompleted this work in accordance with all applicable ordinan s, rules and laws.
<br /> (signature) �Op� (license#) 3 � (date)
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