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END PERFORATION OF A PERFORATED LATERAL <br /> PRESSURE DISTRIBUTION SYSTEM <br /> Wos� Covar <br /> 1. Select number of perforated laterals � Topto11 � <br /> . :,, . . ..,.r. <br /> "''� .'Lcya of GeoteaU�� FaMlc(u fov <br /> .�� Loamy Scnd Loyer :lncn layw ol Iqy x�traw caered <br /> .� ...rit�nd rwln poper) <br /> 2. Select perforation spacing=_�feet. �'�•a ed o M�bro�ion OrI1Nd No�l:omally <br /> � - .. M�o o rw« r� <br /> 3. Since erforations should not be laced closer than 1 ft. to ''�P'°s - � "' �'°" 1z•,° E°a. <br /> P p �Droin Fleld Rxlq of Rock Laye� <br /> the edge of the rock layer(see diagram),subtract 2 ft. from �N''�' ` �� ' ��" ` P.:�o�o�b�'�,.e a� <br /> Clwn So�d Lay�r Bottom of lal�rol <br /> the rock layer length. <br /> o��y�noi sou PropMr gtorlfled <br /> �S - 1 ft. _��feet. ��ae Placlnq Sard Loyw <br /> R°cS`laya�`i'gtt' � TABLE OF PERFORATION DiSCHARGFS IN CPM <br /> 4. Determine the number of spaces between perforations. Head Perfora6on diameter(inches) <br /> Divide the length above by perforation spacing and round ��� ,� <br /> down to neazest whole number. � <br /> i. osb o.� <br /> 7 0.69 0.90 <br /> Length perf. spacing =�(�ft.-:-�ft. _��spaces 2.ob o.so i.oa <br /> �3� �2� 3 0 0 96 1.28 <br /> 5. Number of perforations is equal to one plus the number of a.o 1.13 �.ar <br /> 5.0 7.26 1.65 <br /> perforation spaces . <br /> aUse 1.0 foot of head foz iesidential systems. <br /> bUse 20 Eeet of head for other establishaunts <br /> �spaces + 1 =�perforations/lateral <br /> W.�o�m.Os..bdeb..e(�rrsY .�e�fac�,.r,,,.,,,. . <br /> 6. Multiply perforations per lateral by number of laterals to ,,,,� P"""`'°""�''" <br /> i�m'� 1.25 inch 1 S inch 2.0 inch <br /> get total number of perforations. la �8,.,, 28 <br /> 3 U 13� V7J 26 <br /> u��s x �3a��,= 3�O perforations. a:o i i is 23 <br /> s.o io ia 22 <br /> 7. Determine required flow rate by multiplying <br /> number of perforations by flow per perforation <br /> 3� 0.7 �, .W.�o��„� .. ��.��.� �,�. <br /> �S x���=a 7 m. <br /> S�- � <br /> 8. If laterals are connected to header pipe as shown on upper �- �� <br /> example,to select minimum required lateral diameter;enter �,,.�� <br /> table with perforation spacing and number of perforations �„o,�� <br /> per lateral. Select minimum diameter for \� �'�0 <br /> perforated lateral = .25 inches. <br /> u»ur w rc�rart[o�+[uttWs�a <br /> �(1Yn[M1MIfpM M YOYMD <br /> (JlK/CUIO TK N( . <br /> `R.wrwa v.ae ar Y+� <br /> � �wµi'�n.:ti'w ��//�O <br /> 9. If perforated lateral system is attached to manifold pipe near _,",�i` "-"�` .._... <br /> the center,lower diagram, perforated lateral length and - \,;�`�'�'°��'�'°' L <br /> number of perforations per lateral will be approximately one /,.. �'" "���R-� <br /> half of that in step 8. Using these values, select minimum '' �,,,��� <br /> diameter for perforated lateral = .Z inches. \ ` \r"'�"� <br /> � �y„s <br /> z� <br />