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/ - ,� T , , MOUND DESIGN WORKSHEE7�
<br /> � (For Flows up to 120U gpd)
<br /> 3 �E���n-. ,�s PE� �,T--� o� o���v
<br /> t�. FL,��/,1 Estimatcd Scwagc Flows in Galluns Fxx day
<br />� Estimated �SO gpd (see pages D-7 or I-3, 4, 5) ,,,,,�i �g��
<br /> or measured gpd x 1.5 = ��o�m5 Tr�, Typc II Type Ill TI�
<br /> ,
<br /> B. SEPTIC TANK LIQUID VOLUMES � °� 3°° 2g8 �`
<br /> 4 � 375 256 °�'b`
<br /> a – /oo c� gallons (see pages C-3 or C-5) s �so 4so 2� `�o`
<br /> 6 900 525 332 T��.
<br /> 7 ]OSO 600 370 �
<br /> 8 1200 675 408 cdumn
<br /> C. SOILS (refer to site evaluation}
<br /> 1. Depth to restricting layer = o�6� inches �P��T��kC�p�cilicxin�.���.,,,
<br /> H Numbct o! Minimum Liquid Liquid cnp�iry wi�h
<br /> 2. Depth of percolation tests =/z -r la��¢ i8�� inches ���m= c�.�;h e�.o.��d,t�wi
<br /> �� �� �
<br /> 3. Perco ation rate 3. ao mpi 3or4 ,a,�,
<br /> 4. Land slope 7� `� %o �,a o,9 '�, ��
<br /> o�«9 _.....
<br /> V5i 5i� A-5 f�F2 eTr i � �-f�� ��Je � l9 °l
<br /> D. ROCK LAYER DIMENSIONS
<br /> 1. Multiply flow rate by 0.83 to obtain requireci area of rock
<br /> layer: Daily Flow x 0.83 =
<br /> 5o gpd x 0.83 sq. ft./gpd = �`� sq. ft.
<br /> 2. Select width of rock layer (10 feet or less) = I b ft.
<br /> 3. Length of rock layer = Area = Width = •
<br /> 3� `f sq. ft. = /� ft. = 38 ft. Rock Bed
<br /> :r•r�rtir•r�: :�f�: :�r�r:f:r: i �p�
<br /> tif,r. �`.f�f�f���f,f•r���f����• �'� f
<br /> •ti ti�.,.ti..... .. . . . . . .. ... �ti'idth ,Jft.
<br /> .f�f��.f.f.f�f�,�:;:,•:;:f��.f.;
<br /> E. ROCK VOLLTME ,'��'r'�'"��'��'�'�''�'�'''�'—�1
<br /> Length
<br /> l. Multiply rock area by rock depth to get cubic fee± of rock; 38 � �
<br /> 3� sq. f t. x� f t. _� cu. f t.
<br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards;
<br /> 3�cu. f t. - 27 = l3,9 cu. yd.
<br /> 3. I�lultiply cubic yards by 1.4 to get w�eight of rock in tons;
<br /> 13-9 cu. yd. x 1.4 ton/cu. yd. = 020 tons.
<br /> F. ADSORPTION WIDTH
<br /> Absorptiun Width Sizing't'abic
<br /> 1. Percolation rate in top 12 inci�es of soil is 3. � mpi
<br /> Pcrcola�ion Raic Galbns Raiio of
<br /> 2. Select allowable soil loading rate from table on page E-; in Minutes�� s�;�r�x���e ��d,y�� Absorriion.,;��;,
<br /> � _ gpd�ft2 Inch IMVI) sy�an fcxx I lo Rocl 1:�}cr
<br /> ��� �'id i h
<br /> 3. Calculate adsorption width ratio by dividing rock layer Facter I • c �„� .- _. -
<br /> o.�� s��,� �.zo �.--
<br /> loading rate of 1.20 gpd/ft' by allowable soil loading rate; o.��o ��z �� •• oc�o �.ra
<br /> 6 to 15 Snndy]..oem OJ9 L5,
<br /> 1.20gpd/ft2�-�o gpd%ftz– _�__. �b���o �b�, o.«� 2.«�
<br /> r4, 31 to 4S Sih Loam 0.50 2.:0
<br /> Check this vali�e on pa�Tf.' L-IV. 461060 ClnyLoain 0.45 [.(+i
<br /> 60 �0 120 G�y 0.21 S.IKI
<br /> 4. Multiply adsorption width ratio by rock layer width to get s'�;o;;;�^ c�a� -.... _-.-.
<br /> required adsorption width;
<br /> �— x � ft = _ / D_ ft ,�,; �,,;,,.,,;. .:.f ���, �f«t� :� , ,-- . /;��(
<br /> � .�c..�f �,/,� �
<br /> �� �� �
<br /> _�%" ,r�'p�'^_ � —
<br /> , ��.� � � -
<br /> �i'%/l'�� (_'��'i �i,��: `,r��
<br /> '7��/� %U'i% �fE 1
<br /> `�5��,2�- i:3�%�(r.,j
<br /> � . , ..
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