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2150 Shevlin Drive - 03-117-23-34-0020
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Last modified
8/22/2023 4:37:44 PM
Creation date
10/24/2018 11:21:35 AM
Metadata
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Template:
x Address Old
House Number
2150
Street Name
Shevlin
Street Type
Drive
Address
2150 Shevlin Dr
Document Type
Septic
PIN
0311723340020
Supplemental fields
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. t-ly <br /> � MOUND DESiGIV WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW �-� � <br /> ��„ p g Fsiwrm s[wcE rtpws IM G�lADN3►01�Y <br /> Estimated r rd (see a es D-7 or 1-3,4, 5) ,�,,,a�, T.�. d,�„o�E, — <br /> econoo� t c cx � <br /> or measured gpd. 2 ,� �, �p sox <br /> 3 .b loo :�. a, <br /> • ao0 J7] t3i <br /> B. SEPTIC TANK LIQUID VOLUMES : ,'o ;n ;;� `�` <br /> �� s ixoo s�s .o� c�. <br /> /Uo� _ gallons (see pages C-3 or C-5) <br /> C-3 <br /> C. SOILS (refer to site evaluation) l SEpiiC T�NK c�o.c�nes, iN GALlONS <br /> �� <br /> 1. Depth to restricting layer = � inches "a"``•�.`m <br /> K���d I��YIUY �RIMO�N�O� <br /> �MOY! UOUN Cu�CRt OIf�Of�l <br /> 2. Depth of percolation tests = 1 2- inches ,a,,,. ,�. ,,,, <br /> 3. Percolation rate � mpi �«�� �••� ,,.� <br /> ��. ,.ee �,.o <br /> 4. Land slope � °'o <br /> ,.,a� �.e. �.00 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> ��, gpd x 0.83 sq. ft./gpd =37�sq. ft. <br /> 2. Select width of rock layer (10 feet or less) _ /Q ft. <br /> 3. Length of rock layer = area i width = I <br /> -���a sq. ft. y _� ft. _ � �� ft. Rock Bed <br /> t•t•r•f•v'.r•f•t•�•t•1�I•t.1•f <br /> ti•ti•ti•ti•ti•5�•1•1•ti•ti�ti•ti•ti•ti•�.• T � <br /> � tiftif\f�fti:ti:�:�ftifti:tirti:tif�ftif idth S1� � <br /> ~f•r•f•1•1•1•�'•1•v'•f•t•t•t.l•f <br /> •�•�•~•�•�•~•�•�•���•�•�•�•�• 1 <br /> .r.f.f.f.r.f.f.f.f.f.f.r.f.f.f <br /> E. ROCK VOLUME �'- Length -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; �7 � <br /> 3'7-3 sq. ft. x I ft. �7.�' cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yazds; <br /> �73 cu. f t. 127 = T�-- cu. yd. <br /> 3. Multi�ly cubic yards by 1.4 to get weight of rock in tons; I <br /> I¢•cu. yd. x I.4 ton/cu. yd. =�C�tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is �' mpi E-16 <br /> 2. Select allowable soi� loading rate from table on page E-16; ����R•d�•��o�����, I <br /> ��� Spd/ft2 .-.�.�. .�..,....,,�. � - � <br /> ,.,. �....��.� <br /> 3. Calculate adsorption width ratio by dividing rock layer �""" "'"�� �°" '"" '�'� � <br /> •n. � �.ae Leo I.a o0 <br /> loadin� rate of 1.2Q �pd/ft2 by allowable soil loading rate; "` '" <br /> ,. �o e.o o... .... .o< <br /> 1.._� ci ft�_ d/ft2 = .�•C�C> �•� _�� <br /> ' �F � ' � --� KP .. ..e o.. o.,: .� ,., <br /> u nte o.N o4� •.0 seo <br /> Checic this valtie on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> recuired adsor�rion width; �, <br /> /G� x �. f t = 7�' f t <br /> ; <br /> � <br /> � <br />
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