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1996-008441 - new septic system
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2335 Shadowood Drive - 27-118-23-32-0019
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1996-008441 - new septic system
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Entry Properties
Last modified
8/22/2023 4:20:36 PM
Creation date
8/22/2018 12:09:50 PM
Metadata
Fields
Template:
x Address Old
House Number
2335
Street Name
Shadowood
Street Type
Drive
Address
2335 Shadowood Drive
Document Type
Septic
PIN
2711823320019
Supplemental fields
ProcessedPID
Updated
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(For Flows up to 1200 gpd) <br /> � �.� FGOW . . . . Ba�.�s�.��.o,a�.vaan► <br /> FsHmated�_gpd(see pages D-7 or I-3,4,5) „� � <br /> or measured gpd x 1.5 a . a�. '�'' �'yP'° 7�'�' '� <br /> B. SEPTIC TANK LIQUID�VOLUMES ; � ,'0°,s ='�' � ' <br /> /Z.� .� /�o galloris(s'ee pages C 3 or C 5) s ;o s`s s�`n `; <br /> . oo +� <br /> f <br /> C. SOILS(refer to site evalua�on) � "� � �` "�' � <br /> 1. Depth to restrlcting Iay�_ �y inches ''"`„"`�''•`"''•`�w•• <br /> 2. Depth of pereolaHon tests= �Z inches � �►� `'`��"P�+� <br /> 3. Pereolation rate �'ys mpi � =;a ;; '„o <br /> 4. L111d slope % %i«� �o1J0°oo �0'�000 <br /> D. ROCK LAYER DIMENSIONS <br /> l. Muldply flow rate by 0.83 to obtain r uired area of rock �� ��D� <br /> layer:Daily Flow x �.83= O�,s �1 N <br /> �gpd x 0�9 s .ft./gpd��sq.f� � <br /> 2. Select width of rock Iayer(10 feet or less)_ �� ft. <br /> 3. Length of rock layer=Area+Width� <br /> 7� sq.ft.+ /O ft. � /?5 ft.�Z= 37 S Rock Bed. <br /> • •i)����i • r���i��i���i���� <br /> 1#�f�fti����l=�.�������{�� d1 Sl�ff. <br /> ;s���'{ . :�.�ti{ ��: <br /> E. ROCK VOtUMB t.�„gcu <br /> 1. MulNpty rock area by rock depth to get cubic feet of rock;� � <br /> �0 sq.ft.x � fw��D cu.ft. <br /> 2. Divide cu.fG by 27 cu.ft./cu.yd.fio get rubic yards; <br /> ��' cu.ft. +27= Z�cu. d. �'s ' <br /> 3. MulHply cubic yards by 1.4 to get weight oE rock in tons; '� <br /> �cu.yd.x 1.4 ton/cu.yd. �3�89 tons.. � � <br /> F. ADSORPTION WIDTH /W.5*�b r 40 =3 <br /> 1. Percolallon rate in top 12 inches of soil is 2�5 mpi � A°fO�Du°"�`��'�"��bte � <br /> 2. Select allowable soil loadi�g rate from table on page E-; �� saa,�.. �� �� <br /> . D, g�i/f� w�a� <br /> 3. Calculate adsorption width ratio by dividing rock layer . �.•a�a� c�..s.� . <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; ai as�• �•• a i.o <br /> 6 a li S.nd�l.ar. 0.�9 I.S2 <br /> : 1.20 gpd/ft�+��gpd/ft== Z� . �6a30 t.o.� a6o =.ao <br /> is a 6o sc a�t� a°`30as � <br /> Check this value on page E-16. �,� � Q2� � <br /> 4. Multiply adsorpdon width ratio by rock layer width to get �m... ---- -- <br /> required adsorption width; <br /> Z x �o ft= Z4 ft <br /> t <br /> . � <br />
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