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1995-006820 - new septic system
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2320 Shadowood Drive - 27-118-23-32-0014
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1995-006820 - new septic system
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Last modified
8/22/2023 4:20:13 PM
Creation date
8/22/2018 11:10:41 AM
Metadata
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Template:
x Address Old
House Number
2320
Street Name
Shadowood
Street Type
Drive
Address
2320 Shadowood Drive
Document Type
Septic
PIN
2711823320014
Supplemental fields
ProcessedPID
Updated
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� <br /> t <br /> � _ F-17 <br /> �� . � PiJMP SELECTION PROCEDUItE <br /> El�D PERFORATION OF A PERFORATED LATERA4 <br /> A. Determine pnmp capacity: w�.v... <br /> Gravity Distribution _ T,,,,,,, <br /> 1. Minimum suggested is 600 gallons per liour(10 gpm)to stay ahead of _ ,.. ... ..- <br /> LOr+f ef GwN�1W Fa0/k(e/lai- <br /> Wd�!US2 Td�. '�'•l+�r s.,e tow �Yr„�s,..1 ee..w..r....w <br /> Mr►ns n.r.oov��I <br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 _, �-"'��"'�"'Tw <br /> v..w..�r au�w No.ua�wq <br /> wa Cao� � <br /> , gallons per hour(45 gpm)to prevent build-up oE pressure in drop box. �,.,,,� ;_��.,,, ,_•,.Eav <br /> _. �dei�fMl!Retl� H Rsct lqM <br /> � PV/oMlw Lota1N�1 <br /> - . Pressure Dishbution .. �»..�.,,,�. ���•..«�•�.,., <br /> 3.a. Select number of perforated laterals . <br /> b. Select perforation spacing= feet a'N-'�.w ry.�,�„�. <br /> arr.►1e��S�uC�oyw <br /> � c. Subtract 2 ft from the rock layer length. <br /> ,�,�,,�,�,•2 f�= feet <br />. . d. Determuie the number of spaces between perforations. <br /> � � Length perf:spacing= fG+ ft.= 4paces • Requv�.d Pe�o�aeon Ducn e ' <br /> e. spaces+1= perforations/lateral t��u���+�ce c�� <br /> �_ f. Multiply perforations per lateral by number of laterals to DCseharge � <br /> ," get total numberof perforations. �,�,,,� x-.���= perforations. He�j �'2�� �Ydi'"' <br /> g. � xT�= gpm• � 1.Oa 0.56 0.74 <br /> SELECT��PUNSP CAPACTTY •3� gpm 2.�b �.8� 1.04 <br /> B.Determine head requirements: a.Use for single family homes <br /> 1. Elevation difference between pump and point of discharge. b.Use for all other applications <br /> �feet <br /> � 2. If pumping to a pressure distribution rystem,five feet for pressure <br /> required at manifold if gravity system,zero. <br /> � �_feet <br /> 3. Friction loss <br /> a. Enter friction loss table with gpm and pipe diameter. P;po Lrng�h <br /> Read frictionloss in feet per 100�feet from tably. � ' ' ` � ' Poinc of D'ucharF <br /> , F.L=1. �// f�/100 ft of pipe Fo� 2•o PI/E <br /> b. Determine total pipe length from pump to discharge E�e�auon Dit[errnccl <br /> poinL Add 25 percent to pipe length for fitdng �p <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length-1.25 times pipe length= <br /> F-18b <br /> /75 x 1.25= 2/9 feet <br /> c. CaIculate total friction loss b multi 1 'n 1.5 inch 20 inch 3.0 inch <br /> Y P Yl S �„ F.�a;v,t�.��oo n ar� <br /> friction Ioss in h/100 k by equivalent pipe length. <br /> Total friction loss= 1.y i x Z/ +100= S.3 feet l0 0.69 0.20 <br /> 12 0.96 0.28 <br /> 4. Total head required is the sum of elevation diffemnce, 14 1.28 0.3s <br /> special head requirements,and total friction loss. 16 1.63 O.a8 <br /> 18 203 0.60 <br /> /�� + S + S 20 2a� oas o.ii <br /> ?S 3.73 1.11 0.16 <br /> (1) (2) (3c) 30 5.23 ISS 0.23 <br /> ' 35 7.90 2.06 030 <br /> 40 11.07 2.64 039 <br /> TOTAL HEAD � � feet 45 14.73 3.28 0.48 <br /> SO 3.99 OS8 <br /> C. Pump selection . 6o s:6o o si <br /> � 1. A pump must be selected to deliver at least <br /> .3� gpm (Step A)with at least 2 8� feet of Eotal head (Step B). <br />
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