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<br /> FESSEL MIN( (BOX) MOUND DESIGN WORKSHEET (see Martin��ale letter)
<br /> All boxed rectangles must be enfered,the rest will be calculated. -�- ��-
<br /> � A-1:tsivix�ted Sewage Rov�in C�ctq�s per CkN i
<br /> A. FLOW � �
<br /> Estimated 752.4 gpd(see�gure A-1) ; ������I��
<br /> or measured x 1.5(safety factor)= 9pd � �0� 3 ��$� j ��s U� Ci�ss 131� aaa lU ;
<br /> ��� t �� � :fi0 � ti1,6 ;
<br /> B. SEPTIC TANK LIQUID VOLUMES � � � ��� ` �� ' 219 ' �;tha '
<br /> Septic tank capacit 1,000 Fessel A.T.U. galions(see flgure G-1) ; � ' ��a+1 ! '���� ' �� j ve��es �
<br /> t � ! !tiJ � NJ�� ; �4 � I�il I? �
<br /> C. SOILS(Site evaluation data) ����� ! � � `��� ` �� ; �� � ���• E
<br /> � ? 'C� ` b�'1 3"t�J + :I,�,'iil �
<br /> 1. Depth to restricting layer= 2.17 feet � , j „ ( j ,,� � , �
<br /> ! L LC}� b7� i Qt,a i cc�u��.j
<br /> 2. Depth of percolation tests= 12 inches �-�---�---�-� � �
<br /> 3. Texture Sand Loam
<br /> 4. Soil loading rate(see Figure D-33) 1.27
<br /> Percolation rate 13 MPI
<br /> 5. %Land Slope � % tD•33; ;1b:�1�rpUu�ti V�'idth Slzi��7xhk
<br /> t'�rccXm:�kasc� ~- l.�oaC+ng R.aur i
<br /> . .. . . . . . . . .. ir,;�ti2¢[..-�Nx % Cxni'ir,cture � ::raliw:x j .9h:u�r.a:nn
<br /> c:"-l: �e tie'i`ank t.`a �cifiies tin gallc�ns> rn.r ! � �a�y. t a�u�
<br /> ':`_��l:t. R ........{.,...�.�'c.�...;...,_..._,_......_._.
<br /> � � r � , tt'37ti �Ii�f�G3t�1' � I A ur ifwn 5 � c:ca�5r�.7nd , ?,.�U � �th�
<br /> llJ2��Y��'U. 1LlIl]t .i �.:(.::l: i fr C��k1 1t�14'ii.�l ,. " s �.��.i����,y�.�
<br /> E3rtLtx�r,ia , .i},,i�:.�` ,, �illt c+fs��t7�alh; i
<br /> �d+�')a;t1 trS:xSdi � . � E�nrr,cuua i
<br /> �n
<br /> • lif•msicic .� ����c�.,�a �
<br /> c.01 ��.a.�.t..�.,_ _���__-i,__-�t 4n
<br /> i,t3t�G,Q,�, -�r� �L.�.� ,,, ' c�'10 �, I.n3m �,__y'l f�(t�-'�-.TL- �b0
<br /> r �?i.;.3 l �0 4S S+i 'oun f.� t � I 4q
<br /> „�.i .._.._ _
<br /> a.7 4 1 v,�., i_`JJO �L�,�� .. _._..._, �ilf.._ � .� - --,-
<br /> S Ol'�> 1�.J '��SiJ •: 44 ca GO , .:vmd�4.tm•i 0.4i-' 2 67
<br /> _ 3r�3 �;:��•<,�a:'� - - -
<br /> �._ _� ...__ .
<br /> .8:r� . 'r"r'� . . , .. .. ... �s�rx;:.o�_
<br /> � ..L�u3 ��0 ._. .�. � _.�.�.
<br /> . `^ b to i2V i Saisy�:3ap �-���0.?a -�V � S 00
<br /> ",anGa-S;:tay t
<br /> � ._...ilo��ci�iliwt t2ti'��_.�._,,•'7i�t..�._.�_____..__._. t_..�...,__..__....
<br /> �vuarr•de.:ga.;[w�fl.aa.roi:i mn,�M a4e�ui;Nrliumx»cie
<br /> D. ROCK LAYER DIMENSIONS
<br /> 1. Multiply average design flow(A)by 0.83 to obtain required area of rock layer:Item A x 0.83=
<br /> gpd x 0.83 ftvgpd= ftZ Use 570 Square Feet ......... See System sizing Work Sh�t�
<br /> 2. Determine rock layer width =0.83 ft2lgpd x Linear Loading Rate(LLR)(see LLR chart)
<br /> 0.83 ft2/gpd X �� = ft
<br /> LLR Chart
<br /> Perk Rate LLR
<br /> <120 MPI <=12
<br /> >=120 MPI <=6
<br /> 3. Length of rock layer=area divided by width=
<br /> 570 ftz / 10 feet= 57.0 feet
<br /> E. ROCK VOLUME
<br /> 1. Multiply rock area by rock depth#o get cubic feet of rock
<br /> 570 X 1 ft= 570.0 ft3
<br /> 2. Divide ft3 by 27 ft3lyd3 to get cubic yards
<br /> 570.0 ft3 I 27 = 21.1 yd3
<br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;
<br /> 21.1 yd3 X 1.4 ton/yd3 = 29.6 tons Use 30 Tans
<br /> F. ABSORPTION WIDTH
<br /> 1. Absorption width equals absorption ratio(see Figure D-33)times rock layer width
<br /> 1.5 x 10.0 ft = 15.0 ft
<br />
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