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<br /> PRESSURE DISTRIBUTION SYSTEM �
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<br /> All boxed rectangfes must be entered, fhe rest will be calculated. �L�n���"��"� ��,���� �„v����tK V� �—�'� �� !'
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<br /> 1. Select number of perforated laterals: �
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<br /> 2. Select perforation spacing = �3 ft �E-0:Akn�irnumdia�lera�rriheroft/G-inchptricrntiorxs�
<br /> ;p.n latrrcallo puorantr.e c10%+fiar,horqe vcniplron
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<br /> 3. Since erforations should not be laced closer that 1 foot to `p�`r"`°""" ` � j `
<br /> p p s `
<br /> the edge of the rock layer(see diagram), subtract 2 feet from 4 5A�+�p E �±7�:� ` �.z_s�,�, �.s,,�-.r, � z�oi„�yt,_,i
<br /> the rock layer length 3 �s ; a ` ,c ; �� i � �
<br /> 57 -2 ft= 55 ft ; :•o A• ; �s ; i� � �n �
<br /> rock layer length i '4 ' ' � '� � 10 � � '
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<br /> 4 Determine the number of spaces befinreen perforations. ,
<br /> Divide the length (3) by perforation spacing (2) and round down to nearest whole number.
<br /> Perforation spacing = 55 ft/ 3 ft = 18 spaces
<br /> 5. Number of perforations is equal to one plus the number of perForation spaces (4}.
<br /> `Check figure E-4 to assure the number of perforations per lateral guarantees
<br /> < 90% discharge variation.
<br /> 18 spaces + 1 = 19 perforations/lateral
<br /> 6. A. Total number of perforations = perForations per lateral (5)times number of laterals (1).
<br /> 19 perfs/lat x 3 laterals = 57 perforations �
<br /> £-6: 3��.*rkxc�iion i�ischcx9e in�an
<br /> B. Calculate the square footage per perforation. —
<br /> Should be 6-10 s ft/ erf. Does not a I to at- rades. �e�far�tian dias�r�eter
<br /> q P PP Y 9 ��� incr�es
<br /> 1. Rock bed area = rock width (ft) x rock length (ft) �f,��� 1;8 3j�$ 7 j�2 !Fq '
<br /> 10 ft x 57 ft= 570 ft2 � �Q Q�8 C e�2 i3 5b a��
<br /> 2. Square foot per perforation = Rock Bed Area/number of perfs(6)
<br /> 570.0 ftZ / 57 perfs = 10.0 ftZ/perf 2�Ob t32d �.59 d.80 1.f74
<br /> 5.0 D.41 Q.9� 1,28 ?.+��
<br /> 7. Determine required flow rate by multiplying the total number ::,;,,�,.�;,�.,;;,,;�.,.y�„�,.,,�,,.4,.,_.�,;�•4
<br /> of perforations(6A) by flow per perforations (see figure E-6) - ;�•�-^�}rc�:���'�tlj,r,=;!!}rv�.:a�:•.
<br /> 57 perfs x 0.42 gpm/perfs = 23.9 gpm
<br /> 8. If laterals are connected to header pipe as shown ;.-�x w.:r���
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<br /> in Figure E-1, to select minimum required lateral ���} . =�- �t!� '
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<br /> diameter; enter figure E-4 with perforation spacing (2) and ' �" _ _ �� `" ;
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<br /> number of perforations per lateral (5). � ; �
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<br /> � - � -� � � ; Figu.^e E-l:Mant7otC LooafeC at EnC of Syshsm !
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<br /> Select minimum diameter for perforated laterals = 2.0 inches
<br /> 9. If perforated lateral system is attached to manifold pipe HgureE2:Monifoldlocalotl '"*"� `�' I
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<br /> near the center, like Figure E-2, perForated lateral length (3) � + !
<br /> and number of perforations per lateral (5)will be approximately _ �' �,. `
<br /> 1� � -�• �
<br /> one half of that in step 8. Using these values, select I-� � . , , i
<br /> minimum diameter for perForated lateral = �inches. � �--..� � 4r' !
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<br /> I hereby ce � a have completed this work in accordance with all appiicable ordinances, rules and �aws.
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<br /> (signa.ture) 2656 (license#) 7-8-08 (date)
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