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2008-00139 - septic
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585 Brown Road South - 03-117-23-31-0003
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2008-00139 - septic
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Last modified
8/22/2023 4:36:26 PM
Creation date
7/25/2018 2:24:39 PM
Metadata
Fields
Template:
x Address Old
House Number
585
Street Name
Brown
Street Type
Road
Street Direction
South
Address
585 Brown Rd S
Document Type
Permits/Inspections
PIN
0311723310003
Supplemental fields
ProcessedPID
Updated
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JUN-12-1998 08:18P FROM: T0:9522494616 P:8�13 <br /> � ���� 5.�.� r ��� ��i�c� � �' ���� N <br /> 1V�OUNU DESIGN WORK SHETT' For Flows u to 1200 d <br /> , . <br /> A. Average Design FLOW � � <br /> C���Q �,� A-1: Estlmated Sewage Flows in Gallons per Day <br /> ��� number o <br /> Estimated�gpd(see figure A-1) badrooms c�ass t cias$u �isss w ci�s iv <br /> or measured x].5 (safety factor) 2 soo z2s �eo so% � <br /> _ �d 3 300 218 of the <br /> B. SEPTIC TANK Ca acit � soo 375 25s �ai�es <br /> P y 5 750 450 294 in the <br /> 6 800 525 332 Class I, <br /> '�,.� /7`,�a g�ns`�be���� ` � 1050 600 370 II,or 111 <br /> �� ��� �Jpyu� g 1200 675 40B columns. <br /> 7 <br /> C. SOILS (refer to site evaluation) ��� c-,: $, �kT.,,,�c �w.� M �b� <br /> NumEar oi MGdmum Uquld Uquld mPacNY wUh with�ta�6 <br /> 1. Depth to restrictir►g layer = • feet ��� ���r �ro�a�� in r►swe <br /> 2. Depth of percolation tests=._�• � feet 2��� �� "� 'S°° <br /> 3 or 4 10D0 �1500 200� <br /> 3. Texture r'��'�`�� 1 Z�� �5eas ioo00o 90�00 4a°°°oo <br /> Percolation rate . mpi , 1 <br /> 4. Soil loading rate O. YS gpd/sqft(see figure D-33) C t��1���y���� <br /> 5. Percent land slope�U% $d/�C $/ �! ^1� �� � ��' <br /> D. ROCK L,AYER DIMENSIONS <br /> 1. Mulkiply average design flow (A)by 0.83 to obtain require arock laye���� Z <br /> _,_(�g�_gpd x 0.83 sqft/gpd=�sqft i'�/�a � '"� <br /> 2. Ueterm.ine rock layer width ='0.83 sqft/gpd x lineaz Loading Rate(LLR) <br /> 0.83 sqft/gpd x ��- evd/sqft= c� ft <br /> 3. Len�th of rock layer = area Vwidth= . f <br /> , � sqft(D1) = �f�(D2) _ -��ft 120 MPI <�2 � <br /> i <br /> E. ROCK VOLUME > 120 M P I < G <br /> 1. Muldply rock azea(D1)b rock depth of 1 ft to get cubic feet of rock <br /> . �d sqft x 1 ft=�cuft ' <br /> 2. Divide cuftby 27 cuft/cuyd to get cubic yards <br /> , , G cuft =27 cuyd/cuft= � l - cuyd <br /> 3. Multiply cubic yards by 1.4 to get wei t of rock in tons <br /> �cuyd x 1.4 ton/cuyd =�tons f /o � <br /> 0-93: Abso►Ptfon 1A►ldlh Sizl�Teble <br /> F. SEWAGE ABSORPTION WIDTH w,�� �w� <br /> b YYwros ps� Soll Tww�e f3oYms M�� <br /> lntl� p!f pay lao <br /> Faskr Ipan 5 CmN SOnO 1.� 7.00 <br /> Absorption width equals absorption ratio (See Figure D-33) �� <br /> times rock layer width(D2) <br /> Z�� x�d it=�� ,e a � o�a-< zB� <br /> �� IU��/C�'/'//''/ 61 to 190 �� 0 <br /> I` <br /> �NsfiE / <br /> SC1MA0! i ��0 � � �l ��� �rtraiw�sowbawra <br /> TIlEATMENT �`��^J� <br /> PROGRANI .; <br /> � � � ' m�J� . <br />
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